how do i find the min value using for loop?

2 次查看（过去 30 天）
lakshmi sampath reddy Pulagum
评论： lakshmi sampath reddy Pulagum 2021-11-29
clc
clear all
syms x
for yr = linspace(0,1,10)
f = sin(x);
fL = [0 pi];
iL = [0 pi];
Volume = pi*int((f-yr)^2,iL(1),iL(2));
s=double(Volume)
end
h=min(s)

请先登录，再回答此问题。

采纳的回答

Chunru
Chunru 2021-11-28
Ran in:
syms x
smin = inf; % initialize smin
for yr = linspace(0,1,10)
f = sin(x);
fL = [0 pi];
iL = [0 pi];
Volume = pi*int((f-yr)^2,iL(1),iL(2));
s=double(Volume);
if s<smin,
smin = s;
end
end
%h=min(s)
smin
smin = 0.9437
  8 个评论
显示 6更早的评论
Chunru
Chunru 2021-11-29
Ran in:
syms x
smin = inf; % initialize smin
locmin = nan;
for yr = linspace(0,1,10)
f = sin(x);
fL = [0 pi];
iL = [0 pi];
Volume = pi*int((f-yr)^2,iL(1),iL(2));
s=double(Volume);
if s<smin,
smin = s;
locmin = yr;
end
end
smin, yr
smin = 0.9437
yr = 1
lakshmi sampath reddy Pulagum
lakshmi sampath reddy Pulagum 2021-11-29
ahh it is wrong.its taking yr=1 for max and min too.can you please check it.

请先登录，再进行评论。

更多回答（1 个）

lakshmi sampath reddy Pulagum
thank you soo much.

类别

在 Help Center 和 File Exchange 中查找有关 Assumptions 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by