how to enter mask

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vetri veeran
vetri veeran 2014-10-24
评论： Image Analyst 2014-10-24
Hi sir,
I want to enter this mask given below to 288*543.
288*543 contains initially 1000 as non object and 0 as object.
To that I have to enter this mask,
mask=[1.414,1,1.414; 1,1,1000; 1000,1000,1000];
and I need to apply this algorithm,
d_new(i,j)=min([d_new(i,j);1+d_new(i+1,j); 1.41+d_new(i+1,j+1);1+d_new(i,j+1);1.41+d_new(i-1,j+1)]);
and i need to update the values by d_new(i,j)
How can I achieve this in for loop.
Thanks in advance.

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采纳的回答

Image Analyst
Image Analyst 2014-10-24
Do you mean to replicate the mask out to a size of 288-by-543? Like this:
workspace;
% Initial 3-by-3 mask.
mask=[1.414,1,1.414; 1,1,1000; 1000,1000,1000]
% Make copies out to a size of 288-by-543
mask2 = repmat(mask, [96, 181]);
  1 个评论
Image Analyst
Image Analyst 2014-10-24
Regarding your edited question and new "Answer" (which is the same as your question now, and I'll probably delete)...your mask is 3-by-3 (9 elements) whereas your "algorithm" only has 5 elements. How do you reconcile that?

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更多回答（1 个）

vetri veeran
vetri veeran 2014-10-24
Hi sir,
I want to enter this mask given below to 288*543.
288*543 contains initially 1000 as non object and 0 as object.
To that I have to enter this mask,
mask=[1.414,1,1.414; 1,1,1000; 1000,1000,1000];
and I need to apply this algorithm,
d_new(i,j)=min([d_new(i,j);1+d_new(i+1,j); 1.41+d_new(i+1,j+1);1+d_new(i,j+1);1.41+d_new(i-1,j+1)]);
and i need to update the values by d_new(i,j)
How can I achieve this in for loop.
Thanks in advance.

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