Allocating values in a 3D array using nested for loops
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I've created a 3D array (A) of zeros with dimensions : A=zeros(3,2,4). Using nested for loops I need to overwrite their values so the first value on the first page is 24, and all other values reduce by one each time.
Ex:
A(:,:,1)
24 23
22 21
20 19
A(:,:,2)
18 17
16 15
14 13
Other than pre-allocating A I have no idea where to start, any help would be appreciated.
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James Tursa
2014-10-24
Since this is apparently a homework assignment, I will get you started. Since the requirement is to use nested loops, I assume the instructor wants a loop for each index. So here is the outline, one loop for each index:
A=zeros(3,2,4);
for z = __:__
for y = __:__
for x = __:__
A(x,y,z) = ____;
end
end
end
I will leave it to you to fill in the blanks.
更多回答（1 个）
Azzi Abdelmalek
2014-10-24
A=permute(reshape(24:-1:1,2,3,4),[2 1 3])
2 个评论
Blake Barrows
2014-10-24
Azzi Abdelmalek
2014-10-24
If it's a homework then try something yourself
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