How to enter this program?

2 次查看(过去 30 天)
Hello, I have tried unsuccessfully for a couple hours to enter a program that loops until a number that is even, divisible by both 13 and 16, and whose square root is greater than 120 is found. I have reached a wall, so I have come to ask for help. Would using a while statement be the first step? Please don't solve this problem, I only ask for help getting it going. Yes, this is basic stuff, but I still have little understanding on it.

采纳的回答

Roger Stafford
Roger Stafford 2014-10-25
You need to translate each of those conditions into a matlab logical proposition. For example if n is an integer you are investigating, try dividing it by 13, then comparing the 'round' of the quotient with the original quotient to see if it is still an integer after the division. And yes, the 'while' function is the right thing to use here. Keep it looping until all the conditions turn out to be true for the same integer, for which you can make great use of the "&" operation.
  5 个评论
Rick Rosson
Rick Rosson 2014-10-25
Try using || instead of &&.
Colton
Colton 2014-10-26
@Rick, thank you. That fixed my issues and I was able to find the correct value! And thanks everyone else for the help!

请先登录,再进行评论。

更多回答(2 个)

Rick Rosson
Rick Rosson 2014-10-25
编辑:Rick Rosson 2014-10-25
Here is a faster and simpler approach:
a = 0;
while a < 120^2
a = a + 13*16;
end

per isakson
per isakson 2014-10-26
编辑:per isakson 2014-10-26
Try
>> factor( cssm )
ans =
2 2 2 2 2 5 7 13
where cssm is
function ix = cssm()
% chose a start value, which is larger than 120^2 and divisible by 16
ix = 120*120+16;
while ne( mod(ix,13), 0 )
ix = ix + 16;
end
end

类别

Help CenterFile Exchange 中查找有关 Graph and Network Algorithms 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by