Integral a function handle of two variables with respect to a variable

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f = @(x, y) x+y;
g = @(x) integral(@(y) f(x,y),0,1)
t = (0:0.1:1);
g(t)
It is wrong! How can I get the expected result?

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Walter Roberson
Walter Roberson 2021-12-2
f = @(x, y) x+y;
g = @(x) integral(@(y) f(x,y), 0, 1, 'arrayvalued', true)
g = function_handle with value:
@(x)integral(@(y)f(x,y),0,1,'arrayvalued',true)
t = (0:0.1:1);
g(t)
ans = 1×11
0.5000 0.6000 0.7000 0.8000 0.9000 1.0000 1.1000 1.2000 1.3000 1.4000 1.5000

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