display Empty matrix: 1-by-0
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here is the question :
function can return a vector as a result. Write a function vecout that will receive
one integer argument and will return a vector that increments from the value of
the input argument to its value plus 5, using the colon operator.
I got : function vector= vecout(integer)
start= integer;
end= integer + 5;
vector= start:end;
end
The answer display Empty matrix: 1-by-0 What should I fix this porblem
采纳的回答
Mohammad Abouali
2014-10-26
编辑：Mohammad Abouali
2014-10-26
This is very tricky
You can not use end as a variable name. That is a reserved word.
SO pretty much your definition of the function:
function vector= vecout(integer)
start= integer;
end = integer + 5;
vector= start:end;
end
becomes:
function vector= vecout(integer)
start= integer;
end
everything after the first "end" is ignored so vector is never assigned anything; thus returning as an empty array.
Correct it this way
function vector=vecout(n)
vector=n:n+5;
end
4 个评论
david Chan
2014-10-26
Mohammad Abouali
2014-10-26
编辑：Mohammad Abouali
2014-10-26
n:n-5 returns a null vector.
Because n-5 is definitely smaller than n so that generates nothing. If you want it to generate something it should be n:-1:n-5. Then it starts going down (-1 step) to reach n-5. With plus n:+1:n+5 but since +1 is the default step you can omit it and just type n:n+5. That's why one works and the other doesn't.
david Chan
2014-10-26
Mohammad Abouali
2014-10-26
You are welcome
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