Indexing cannot yield multiple results error

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Joao
Joao 2014-10-27
编辑： Stephen23 2016-2-6
Hello! I have this function:
function [E1x,E2x]=coupler(Eax,Ebx,Npt1)
n=1;
Eout=zeros(Npt1,2);
E1x=zeros(Npt1,1);
E2x=zeros(Npt1,1);
while n<=Npt1
Enew=[Eax(n); Ebx(n)];
c=[sqrt(0.5) 1i*sqrt(0.5);1i*sqrt(0.5) sqrt(0.5)];
Eout(n,:)=c*Enew;
E1x(n)=Eout(n,1);
E2x(n)=Eout(n,2);
n=n+1;
end
end
I am calling this function like this:
[E11x,E22x] = coupler(Eaf1,Ebf1,Npt);
However the error appears: Indexing cannot yield multiple results. What am I doing wrong?
Best regards, João
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Joao
Joao 2014-10-27
Yes i had another variable called coupler. Many thanks!!
Adam
Adam 2014-10-27
I'll add it as an answer then in case anyone comes to this thread in future with the same problem. I didn't want to put it as an answer first since I wasn't 100% sure if that was the problem.

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采纳的回答

Adam
Adam 2014-10-27
编辑：Adam 2014-10-27
Check that you do not also have a variable called 'coupler' which will stop Matlab from being able to see your function.
If you have a variable, 'coupler', then the line:
[E11x,E22x] = coupler(Eaf1,Ebf1,Npt);
will attempt to index into that variable, rather than calling your function, which will result in the error you showed as indexing into a variable cannot return two outputs.
As Star Strider points out, you can type:
which coupler -all
to check if you have a variable called 'coupler'. If you get a variable returned here as well as your function then that is the problem.

更多回答（1 个）

BHANESH BHADRECHA
That is because you have created any loop and in that loop variable is changing its value every time loop executes.
The best way is to clear variables that are defined in that loop.
clear this variables before the loop ends.....
for example
for i=1:1000 j=stft(x); k=max(j); clear j; clear k; end

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