Indexing cannot yield multiple results error

Question

Joao 2014-10-27

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/160281-indexing-cannot-yield-multiple-results-error

编辑： Stephen23 2016-2-6

Hello! I have this function:

function [E1x,E2x]=coupler(Eax,Ebx,Npt1)
n=1;
Eout=zeros(Npt1,2);
E1x=zeros(Npt1,1);
E2x=zeros(Npt1,1);
while n<=Npt1
Enew=[Eax(n); Ebx(n)];
c=[sqrt(0.5) 1i*sqrt(0.5);1i*sqrt(0.5) sqrt(0.5)];
Eout(n,:)=c*Enew;
E1x(n)=Eout(n,1);
E2x(n)=Eout(n,2);
n=n+1;
end
end

I am calling this function like this:

[E11x,E22x] = coupler(Eaf1,Ebf1,Npt);

However the error appears: Indexing cannot yield multiple results. What am I doing wrong?

Best regards, João

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Joao 2014-10-27

Yes i had another variable called coupler. Many thanks!!

Adam 2014-10-27

I'll add it as an answer then in case anyone comes to this thread in future with the same problem. I didn't want to put it as an answer first since I wasn't 100% sure if that was the problem.

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Answer 1

Adam 2014-10-27

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/160281-indexing-cannot-yield-multiple-results-error#answer_156752

编辑：Adam 2014-10-27

在 MATLAB Online 中打开

Check that you do not also have a variable called 'coupler' which will stop Matlab from being able to see your function.

If you have a variable, 'coupler', then the line:

[E11x,E22x] = coupler(Eaf1,Ebf1,Npt);

will attempt to index into that variable, rather than calling your function, which will result in the error you showed as indexing into a variable cannot return two outputs.

As Star Strider points out, you can type:

which coupler -all

to check if you have a variable called 'coupler'. If you get a variable returned here as well as your function then that is the problem.