Add zero decimal digits in order to have all the elements of a matrix with same number of decimal digits

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How can I add zero decimal digits to a number in order to have the same number of decimal digits in the numbers of a matrix? For instance, if I have only a "27" how can I change it to a "27.000"? I have already tried the function
compose("%.3f",A)
in order to have the same decimal formt of all the elements of matrix A, but it does not work.

采纳的回答

Walter Roberson
Walter Roberson 2021-12-4
编辑:Walter Roberson 2021-12-5
I already showed you how to use compose with a format to get a fixed number of digits.
  14 个评论
Walter Roberson
Walter Roberson 2021-12-6
take the result of the standardizeMissing and array2table() with 'VariableNames' set to the header for the column. writetable() the results.
Walter Roberson
Walter Roberson 2021-12-6
https://www.mathworks.com/matlabcentral/answers/1601825-how-to-use-ismember-to-check-if-an-inputted-number-exists-in-a-matrix#comment_1868585 has more background about text files.

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更多回答(2 个)

Rik
Rik 2021-12-4
There is a distinction between the way data is stored and how it is displayed.
You can change the data type (double, single, cell, char, etc) to change the underlying data.
You can use functions like fprintf and sprintf to display your data a certain way.
  12 个评论
Rik
Rik 2021-12-5
Did you not see the if statement? The loop I showed will write only 1 value at a time, so you have full control over the format.
But the solution Walter showed you will also work.
Emilio Pulli
Emilio Pulli 2021-12-6
Thank you man! I use the Walter answer because was faster, but also your advices helped me understanding better the problem! Thank you again for the patience!

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G A
G A 2021-12-4
A = magic(3)
A = 3×3
8 1 6 3 5 7 4 9 2
B = num2str(A,'%.3f\t')
B = 3×17 char array
'8.000→1.000→6.000' '3.000→5.000→7.000' '4.000→9.000→2.000'

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