Extending the vector length

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VG
VG 2021-12-7
回答： KSSV 2021-12-7
I have a signal with sampling frequency of 20000 and the total lenght of the signal is 200010. Now I want to take a paticular sample around 181600 and give a new variable but I am encountering an error (Index exceeds array bounds.). I could understand clearly that the orginal lenth is less thamn the new length.
Now how should I add zeros to the orginal vector (ch_x1_interval_1) so that it should extend with zeros to the remaining data to get the new signal.
Below is the code that I used it would be very nice to give comments to the code given below.
ch_x1_interval_1_new =ch_x1_interval_1(181600:181600+20000);
Thank you.
  1 个评论
VG
VG 2021-12-7
I tried doing it manually by adding zeros and it worked.But its the hard way to do that.

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回答（1 个）

KSSV
KSSV 2021-12-7
Two options.
Option 1:Use interpolation to extend the size.
n = length(ch_x1_interval_1) ;
x = 1:n ;
xi = linspace(1,n,181600) ;
iwant = interp1(x,ch_x1_interval_1,xi) ;
Option 2: Appending zeros
n = length(ch_x1_interval_1) ;
m = 181600 ;
iwant = zeros(1,m) ;
iwant(1:n) = ch_x1_interval_1 ;

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