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I have a problem with the app designer . The graph instead of appearing in the app , it appears in a new window as the attached photo shows

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Steven Lord
Steven Lord 2021-12-8
Please show us the code you wrote that tries to create that plot in the app.
Here it is :
classdef mn21hmya_GUI < matlab.apps.AppBase
% Properties that correspond to app components
properties (Access = public)
UIFigure matlab.ui.Figure
TextArea matlab.ui.control.TextArea
TextAreaLabel matlab.ui.control.Label
PlotFitButton matlab.ui.control.Button
FitLineButton matlab.ui.control.Button
LoadDataButton matlab.ui.control.Button
UIAxes matlab.ui.control.UIAxes
end
properties (Access = private)
data % data information
voltage % Description
displacement % Description
voltage_fit % Description
displacement_fit % Description
coeffs % Description
end
% Callbacks that handle component events
methods (Access = private)
% Button pushed function: LoadDataButton
function LoadDataButtonPushed(app, event)
app.data = dlmread('sensor_calibration.txt', '\t',1,0);
app.data = dlmread('sensor_calibration.txt', '\t',1,0);
app.displacement = app.data(:,1);
app.voltage = app.data(:,2);
app.FitLineButton.Enable = 'on'
end
% Button pushed function: FitLineButton
function FitLineButtonPushed(app, event)
app.displacement = app.data(:,1);
app.voltage = app.data(:,2);
% There is a linear relationship between voltage and
% displacement. Use polyfit function to determine the relationship such
% that displacement = gain*voltage + offset. Find the two variables
% gain and offset.
app.coeffs = polyfit(app.voltage, app.displacement, 1);
gain = app.coeffs(1);
offset = app.coeffs(2);
% Display the equation relating voltage to displacement using fprintf
if offset < 0
fprintf('The relationship between distance and voltage is D = %.3fV %.3f\n',gain, offset)
else
fprintf('The relationship between distance and voltage is D = %.3fV +%.3f\n',gain, offset)
end
app.PlotFitButton.Enable = 'on'
end
% Button pushed function: PlotFitButton
function PlotFitButtonPushed(app, event)
% Create a new vector that starts at 0 and goes
% up to 7 in steps of 0.5. Assign to a column vector voltage_fit.
app.voltage_fit = 0:0.5:7;
app.voltage_fit = app.voltage_fit';
% Create a new vector, displacement_fit, for the line of
% best fit. It should be a column vector the same length as voltage_fit
% found using the calibration equation.
app.displacement_fit = polyval(app.coeffs, app.voltage_fit);
% Plot the measured displacement against voltage that came from
% the file, and the modelled line of best fit on the same figure.
% Label appropriately.
figure(1)
plot(app.voltage, app.displacement)
xlabel('voltage (v)')
ylabel('displacement (mm)')
hold on
plot(app.voltage_fit, app.displacement_fit)
legend('Raw data', 'Line fit')
hold off
end
end
% Component initialization
methods (Access = private)
% Create UIFigure and components
function createComponents(app)
% Create UIFigure and hide until all components are created
app.UIFigure = uifigure('Visible', 'off');
app.UIFigure.Position = [100 100 640 480];
app.UIFigure.Name = 'MATLAB App';
% Create UIAxes
app.UIAxes = uiaxes(app.UIFigure);
title(app.UIAxes, 'Title')
xlabel(app.UIAxes, 'X')
ylabel(app.UIAxes, 'Y')
zlabel(app.UIAxes, 'Z')
app.UIAxes.Position = [120 55 345 214];
% Create LoadDataButton
app.LoadDataButton = uibutton(app.UIFigure, 'push');
app.LoadDataButton.ButtonPushedFcn = createCallbackFcn(app, @LoadDataButtonPushed, true);
app.LoadDataButton.Position = [50 403 100 22];
app.LoadDataButton.Text = ' Load Data';
% Create FitLineButton
app.FitLineButton = uibutton(app.UIFigure, 'push');
app.FitLineButton.ButtonPushedFcn = createCallbackFcn(app, @FitLineButtonPushed, true);
app.FitLineButton.Enable = 'off';
app.FitLineButton.Position = [261 403 100 22];
app.FitLineButton.Text = 'Fit Line';
% Create PlotFitButton
app.PlotFitButton = uibutton(app.UIFigure, 'push');
app.PlotFitButton.ButtonPushedFcn = createCallbackFcn(app, @PlotFitButtonPushed, true);
app.PlotFitButton.Enable = 'off';
app.PlotFitButton.Position = [464 403 100 22];
app.PlotFitButton.Text = 'Plot Fit';
% Create TextAreaLabel
app.TextAreaLabel = uilabel(app.UIFigure);
app.TextAreaLabel.HorizontalAlignment = 'right';
app.TextAreaLabel.Position = [50 343 56 22];
app.TextAreaLabel.Text = 'Text Area';
% Create TextArea
app.TextArea = uitextarea(app.UIFigure);
app.TextArea.Position = [121 307 150 60];
% Show the figure after all components are created
app.UIFigure.Visible = 'on';
end
end
% App creation and deletion
methods (Access = public)
% Construct app
function app = mn21hmya_GUI
% Create UIFigure and components
createComponents(app)
% Register the app with App Designer
registerApp(app, app.UIFigure)
if nargout == 0
clear app
end
end
% Code that executes before app deletion
function delete(app)
% Delete UIFigure when app is deleted
delete(app.UIFigure)
end
end
end

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 采纳的回答

0 个投票

in PlotFitButtonPushed function which you plot your graphs, by using figure you create new figure out of your app.UIFigure. use axes(app.UIAxes) to select the Axes in app as current Axes. or just add Axes to plot.
function PlotFitButtonPushed(app, event)
% Create a new vector that starts at 0 and goes
% up to 7 in steps of 0.5. Assign to a column vector voltage_fit.
app.voltage_fit = 0:0.5:7;
app.voltage_fit = app.voltage_fit';
% Create a new vector, displacement_fit, for the line of
% best fit. It should be a column vector the same length as voltage_fit
% found using the calibration equation.
app.displacement_fit = polyval(app.coeffs, app.voltage_fit);
% Plot the measured displacement against voltage that came from
% the file, and the modelled line of best fit on the same figure.
% Label appropriately.
axes(app.UIAxes)
plot(app.UIAxes,app.voltage, app.displacement)
% or just plot(app.voltage, app.displacement) because you make
% app.UIAxes curent Axes
xlabel(app.UIAxes,'voltage (v)')
ylabel(app.UIAxes,'displacement (mm)')
hold(app.UIAxes,'on')
% or just hold on
plot(app.voltage_fit, app.displacement_fit)
legend('Raw data', 'Line fit')
hold(app.UIAxes,'off')
end

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@Abolfazl Chaman Motlagh Thanks for getting back, it works now.
Another samll question if I wnat to add text in 'text area' I just write on it , right? The one that with fprintf .
Happy to Help.
Yes you can just write on it. and also if you want to change the text in code or during process you can use Value field to edit :
app.TextArea.Value = {'Sample Text' ; 'Sample Text 2'};
this will write 2 lines for example.

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更多回答（1 个）

Peter Bonavita
Peter Bonavita 2021-12-8

0 个投票

Hi Hassen,
I understand your app generates a plot, but the plot appears in a figure outside the app. In your app's call to plot, you can specify the axis where you want the plot to appear.
Check out lines 70-71 of the .MLAPP file from this example. You can open the app using this command, then view the code shown below in the code view:
>> openExample('matlab/MortgageCalculatorExample')
Here's the code, in this case it shows the plot targets the axis at app.PrincipalInterestUIAxes
% Plot the principal and interest
plot(app.PrincipalInterestUIAxes,(1:nper)',principal, ...
(1:nper)',interest);
legend(app.PrincipalInterestUIAxes,{'Principal','Interest'},'Location','Best')
xlim(app.PrincipalInterestUIAxes,[0 nper]);
I wasn't able to reproduce using your app but it looks like you'll just need to add app.UIAxes in your calls to plot, something like:
plot(app.UIAxes, app.voltage, app.displacement)
Hope this helps,
Peter

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