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Convert ezmesh to fmesh

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CL
CL 2021-12-9
评论： KSSV 2021-12-10
I have an old piece of code that uses ezmesh:
h=ezmesh(@(x,y)v1(1)*x+v2(1)*y,... % funx
@(x,y)v1(2)*x+v2(2)*y,... % funy
@(x,y)v1(3)*x+v2(3)*y,... % funz
[-1 1 -1 1 -1 1]); % interval
In version R2021b, the editor prompts a warning that says:
'ezmesh' is not recommended. With appropriate code changes, use 'fmesh' instead
But after I convert ezmesh to fmesh:
h=fmesh(@(x,y)v1(1)*x+v2(1)*y,... % function of x
@(x,y)v1(2)*x+v2(2)*y,... % function of y
@(x,y)v1(3)*x+v2(3)*y,... % function of z
[-1 1 -1 1 -1 1]); % interval
I get the following warning:
Error using fsurf (line xxx)
Invalid parameter '-1 1 -...'.
Error in fmesh (line xxx)
h = fsurf(varargin{:}, 'CalledForMesh');
Error in xxx (line xxx)
h=fmesh(@(x,y)v1(1)*x+v2(1)*y,... % function of x
Can someone help explain what the problem is?

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回答（1 个）

KSSV
KSSV 2021-12-9
编辑：KSSV 2021-12-10
Ran in:
v1 = rand(3,1) ;
v2 = rand(3,1) ;
h=fmesh(@(x,y)v1(1)*x+v2(1)*y,... % funx
@(x,y)v1(2)*x+v2(2)*y,... % funy
@(x,y)v1(3)*x+v2(3)*y,... % funz
[-1 1 -1 1]); % interval
  2 个评论
CL
CL 2021-12-10
sorry I'm not getting this. Why did you only specify one inteval [-1,1] for x-axis and ignoreing y- and z-axis? In the image shown, x's axis has [-0.4,0.4], y's axis has [-0.5,0.5] and z's [-1.3,1.3] ... none of the axis shown inteval of [-1,1].
KSSV
KSSV 2021-12-10
You can specify the intervel for x and y. Edited the code.

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