error when call function
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hello,
I use matlab for excercises on the university. I declare a function 'benadering_four' and when I ask for benadering_four(0) (so 0 put in the function) then it works but when I put a vector in the function (in the code, benadering_four(xx) ) then it gives me the error:
*Error using * Inner matrix dimensions must agree.
Error in @(y)[1,cos([1:floor(n/2)]*y),sin([1:floor(n/2)]*y)]
Error in @(y)Fourier(pi*y)*coef_four*
xx = -1:0.001:1;
n = 9;
coef_four = 1/pi*[pi*atan(5)/5; 1.08104; .552133; .30444; .157123; 0; 0; 0; 0]
Fourier = @(y) [1 cos([1:floor(n/2)]*y) sin([1:floor(n/2)]*y)]
benadering_four = @(y) Fourier(pi*y)*coef_four
benadering_four(0)
benadering_four(xx)
I doesn't understand why it works with an number and why it doesn't work with a vector. Can someone help me?
采纳的回答
cos([1:floor(n/2)]*y
will only be valid syntax for y being a vector in very specific circumstances - i.e. if they are the same length and one is a row vector, the other is a column vector. Depending which way round they are in that case you either get a scalar result or a square matrix result.
In all other cases you get a syntax error because you cannot do matrix multiplication (or indeed element-wise multiplication) on two arbitrary vectors of different lengths.
In this case I don't know what your expectations would be from passing a vector in. Do you expect a 3-element vector out? If so then y needs to be a column vector of length n.
4 个评论
Adam
2014-10-30
Well if floor(n/2) is 4 then [1:floor(n/2)] is going to be a length 4 vector. You can't multiply a length 4 vector by whatever the length of xx is (2001 in this case).
The size of coef_four is not the problem, the error is in the Fourier part of the function.
Adam
2014-10-30
Try transposing xx or whatever you are passing in.
You can do matrix multiplication if you have a row vector and column vector but not two of the same.
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