not compatible with the size

1 次查看(过去 30 天)
itr=0; % number of iteration
for t=1:1:3
itr=itr+1;
b(itr)=[sin(t) cos(t)];
end
In the above code , I am getting the error " Unable to perform assignment because the indices on the left side are not compatible with the size of the right side."
Please tell me how to fix.

采纳的回答

Chunru
Chunru 2021-12-11
itr=0; % number of iteration
for t=1:1:3
itr=itr+1;
b(itr, :)=[sin(t) cos(t)]; % Two numbers for each iteration form a row for a matrix b (nitr x 2)
end
b
b = 3×2
0.8415 0.5403 0.9093 -0.4161 0.1411 -0.9900
  4 个评论
Chunru
Chunru 2021-12-12
itr=0; % number of iteration
for t=1:1:3
itr=itr+1;
b(itr, :)=[sin(t) cos(t)];
c(itr, :)=[1-sin(t) 1];
end
d=[b c]
d = 3×4
0.8415 0.5403 0.1585 1.0000 0.9093 -0.4161 0.0907 1.0000 0.1411 -0.9900 0.8589 1.0000

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Shifting and Sorting Matrices 的更多信息

产品


版本

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by