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Can anyone pls help me with the following code;

1 次查看（过去 30 天）
Shenbagalakshmi Veliah
关闭： MATLAB Answer Bot 2021-8-20
choice=input('enter a no.to be recognized:no.1 for trained words,no.2 for not trained words:');
if choice==1)
[pathname,filename]=uigetfile('*.wav','Select a wave file');
current=strcat(filename,pathname);
input=wavread(current);
disp('y');
else
disp('n');
end
when i give input as 1,then it must enter into 'if'loop or else it should enter into else condition.

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回答（1 个）

Harry
Harry 2014-11-2
Your code is mostly correct, just remove the ")" at the end of your 'if' statement:
if choice==1
  2 个评论
Shenbagalakshmi Veliah
Shenbagalakshmi Veliah 2014-11-2
Thank u very much for ur reply Harry.But my problem is that for the first time if i entered '1'it enters the loop and it gets displayed as 'y',for second time if i run the same program it does not ask me the input.so i think the execution itself is stopped for only once.can u pls help me with this problem.
Harry
Harry 2014-11-3
编辑：Harry 2014-11-3
Ah yes, your problem is that you have named a variable "input"... but you also need to use a function called "input".
Therefore, when you create the variable input=wavread(current), this means you can't call the function choice=input(...) any more.
The easy solution is to rename your variable "input". For example, try this:
choice=input('enter a no.to be recognized:no.1 for trained words,no.2 for not trained words:');
if choice==1
[pathname,filename]=uigetfile('*.wav','Select a wave file');
current=strcat(filename,pathname);
wave=wavread(current);
disp('y');
else
disp('n');
end
In the future, you should always clear all your variables at the start of your code, using:
clear all;
This will prevent many problems like this from happening.

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