Problem to display output

2021 12 13
1 个回答
更新时间：2021 12 13
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0 个投票

Hi, I have a problem to display the output. Can someone help me to solve this? Thanks a lots!
Below here are the codes:
for i = 1:3
trans_matrix = trans_matrix + diag(ones(N-i,1),i);
end
for n = 1: length(ladder_Start)
b = trans_matrix(:,ladder_End(n));
trans_matrix(:,ladder_End(n)) = trans_matrix(:,ladder_Start(n)) + b;
trans_matrix(:,ladder_Start(n)) = zeros(1,N);
b = [];
end
for n = 1: length(snake_Head)
b = trans_matrix(:,snake_Tail(n));
trans_matrix(:,snake_Tail(n)) = trans_matrix(:,snake_Head(n)) + b;
trans_matrix(:,snake_Head(n)) = zeros(1,N);
b = [];
end
b = trans_matrix;
trans_matrix = (1/3)*b;
b = [];
ITERATIONS = 200;
d=zeros(1,ITERATIONS);
for i = 1:200
b = trans_matrix^i;
d(i) = b(N+1,1);
end
b=[];
At the command window there it shows the error of this.

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Mathieu NOE
Mathieu NOE 2021-12-13
hello
some info's are missing like :
how is initilaized trans_matrix, ladder_Start,snake_Head
Deck Zhan Sim
Deck Zhan Sim 2021-12-13
trans_matrix = zeros(25,25);
ladder_Start = [3, 9, 17];
ladder_End = [7, 18, 24];
snake_Head = [16, 20, 23];
snake_Tail = [5, 12, 19];
N = 25;
Mathieu NOE Hi, this is the initilaized code that you mention

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回答（1 个）

Rik
Rik 2021-12-13
Ran in:

0 个投票

Ran in:
You're trying to index b. So let's explore the values involved:
%rest of your code
for i = 1:200
b = trans_matrix^i;
disp(b)
disp(N+1)
d(i) = b(N+1,1);
end
Columns 1 through 22 0 0.3333 0 0.3333 0 0 0.3333 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0.3333 0.3333 0 0.3333 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0.3333 0.3333 0.3333 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0.3333 0.3333 0.3333 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0.3333 0.3333 0.3333 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0.3333 0.3333 0 0 0 0 0 0 0 0 0 0.3333 0 0 0 0 0 0 0 0 0 0 0 0.3333 0 0.3333 0 0 0 0 0 0 0 0.3333 0 0 0 0 0 0 0 0 0 0 0 0 0 0.3333 0.3333 0 0 0 0 0 0 0.3333 0 0 0 0 0 0 0 0 0 0 0 0 0 0.3333 0.3333 0.3333 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0.3333 0.3333 0.3333 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0.3333 0.3333 0.3333 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0.3333 0.3333 0.3333 0 0 0 0 0 0 0 0 0 0 0 0.3333 0 0 0 0 0 0 0 0 0.3333 0.3333 0 0 0 0 0 0 0 0 0 0 0 0.3333 0 0 0 0 0 0 0 0 0 0.3333 0 0 0 0 0 0 0 0 0 0 0 0.3333 0 0 0 0 0 0 0 0 0 0 0 0 0.3333 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0.3333 0.3333 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0.3333 0 0 0 0 0 0.3333 0.3333 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0.3333 0 0 0 0 0 0 0.3333 0 0.3333 0 0 0 0 0 0 0 0 0 0 0 0 0.3333 0 0 0 0 0 0 0 0 0.3333 0.3333 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0.3333 0 0.3333 0.3333 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0.3333 0 0 0.3333 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0.3333 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 Columns 23 through 25 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0.3333 0 0 0.3333 0 0 0.3333 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0.3333 0 0 0.3333 0.3333 0 0.3333 0.3333 0 0 0.3333 0 0 0
26
Index in position 1 exceeds array bounds. Index must not exceed 25.
So you have a 25x25 matrix, and you try to get the first value from the 26th row. It doesn't exist, so Matlab throws the error.
Since you didn't include any comments in your code and used obfuscating names like b and d as variable names, it is impossible to understand what is happening or what the intended function was. It is therefore extremely difficult to suggest a change in your code.
This is about as self-documenting before minifying it as afterwards:
v000=zeros(25,25);v001=[3, 9, 17];v002=[7, 18, 24];v003=[16, 20, 23];v004=...
[5, 12, 19];v005=25;for v006=1:3,v000=v000 + diag(ones(v005-v006,1),v006);
end,for v007=1: length(v001),v008=v000(:,v002(v007));v000(:,v002(v007))=...
v000(:,v001(v007)) + v008;v000(:,v001(v007))=zeros(1,v005);v008=[];end,for ...
v007=1: length(v003),v008=v000(:,v004(v007));v000(:,v004(v007))=v000(:,...
v003(v007)) + v008;v000(:,v003(v007))=zeros(1,v005);v008=[];end,v008=v000;
v000=(1/3)*v008;v008=[];v009=200;v010=zeros(1,v009);for v006=1:200,v008=...
v000^v006;v010(v006)=v008(v005+1,1);end,v008=[];

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Rik
Rik
2021-12-13

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