Why last line of the code says "Error using reshape Size arguments must be real integers."

1 次查看(过去 30 天)
n = 256; % Number of bits to process
x = randint(n,1); % Random binary data stream
M = 16; % Size of signal constellation
k = log2(M); % Number of bits per symbol
xsym = bi2de(reshape(x,k,length(x)/k).','left-msb');

回答(1 个)

Ashutosh Singh Baghel
Hi nur,
I understand you want to generate a random stream of 1's and 0's. According to the R2016b release notes, it clearly states - '"Replace all instances of randint with randi."
'randint(1,1,[1,n])' would now be written as 'randi([1,n],1,1)'.
Please see the following example -
n = 256; % Number of bits to process
A = randi([0 1],n,1); % Random binary data stream
Also, using reshape function , the syntax is as -
k = 8;
B = reshape(A,[k,n/k]);
size(A)
ans = 1×2
256 1
size(B)
ans = 1×2
8 32
Please follow the MATLAB Documnetation link for 'reshape','randi' and 'R2016b release notes.'

类别

Help CenterFile Exchange 中查找有关 Test and Measurement 的更多信息

产品


版本

R2019b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by