How to get polynomial equation of polyfit?

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Hello. I have the following code and the data. I need to find the equation of the polynomial and write it on the graph. Also, I will be changing the x and y datas so, it needs to be specific for a set of datas. Thank you for your help! It will be appreciated!!
clc;
clear;
y = [4.0432,4.1073,4.0899,4.1319,4.2885,4.4305,4.5249,4.6172,4.6962,4.7235,4.5987,4.7927,4.895,4.9079];
x = [1999,2000,2001,2002,2003,2004,2005,2006,2007,2008,2009,2010,2011,2012];
pf = polyfit(x,y,2);%Calculating the corresponding polynomial function
disp('The coefficients of the desired polynomial:');
fprintf('%3.3f\n',pf) %Showing the coefficients of the fitted polynomial function
pv = polyval(pf,x);%Calculating the values of polynomial function at x's
disp('The values of polynomial at given set of x values:');
fprintf('\n %3.3f',pv)
scatter(x,y)
hold on
plot(x,pv)
hold off
  2 个评论
Rik
Rik 2021-12-14
You already have the vector with the coefficients. You are also aware of how to use fprintf, so the step to sprintf is minimal. What exactly is the output you would like?
berk26092
berk26092 2021-12-14
This is the simple linear regression line for my data and there is the equation of the line. I would like to find the equation of second order polynomial and show the equation on the figure as below.

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采纳的回答

Mathieu NOE
Mathieu NOE 2021-12-14
hello
my suggestion below :
the equation is given by the string eqn
code :
clc;
clear;
y = [4.0432,4.1073,4.0899,4.1319,4.2885,4.4305,4.5249,4.6172,4.6962,4.7235,4.5987,4.7927,4.895,4.9079];
x = [1999,2000,2001,2002,2003,2004,2005,2006,2007,2008,2009,2010,2011,2012];
% Fit a polynomial p of degree "degree" to the (x,y) data:
degree = 2;
p = polyfit(x,y,degree);
% Evaluate the fitted polynomial p and plot:
f = polyval(p,x);
eqn = poly_equation(flip(p)); % polynomial equation (string)
Rsquared = my_Rsquared_coeff(y,f); % correlation coefficient
figure(3);plot(x,y,'o',x,f,'-')
legend('data',eqn)
title(['Data fit - R squared = ' num2str(Rsquared)]);
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
function Rsquared = my_Rsquared_coeff(data,data_fit)
% R2 correlation coefficient computation
% The total sum of squares
sum_of_squares = sum((data-mean(data)).^2);
% The sum of squares of residuals, also called the residual sum of squares:
sum_of_squares_of_residuals = sum((data-data_fit).^2);
% definition of the coefficient of correlation is
Rsquared = 1 - sum_of_squares_of_residuals/sum_of_squares;
end
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
function eqn = poly_equation(a_hat)
eqn = " y = "+a_hat(1);
for i = 2:(length(a_hat))
if sign(a_hat(i))>0
str = " + ";
else
str = " ";
end
if i == 2
eqn = eqn+str+a_hat(i)+"*x";
else
eqn = eqn+str+a_hat(i)+"*x^"+(i-1)+" ";
end
end
eqn = eqn+" ";
end
  4 个评论
Mathieu NOE
Mathieu NOE 2021-12-14
version 2
clc;
clear;
y = [4.0432,4.1073,4.0899,4.1319,4.2885,4.4305,4.5249,4.6172,4.6962,4.7235,4.5987,4.7927,4.895,4.9079];
x = [1999,2000,2001,2002,2003,2004,2005,2006,2007,2008,2009,2010,2011,2012];
% Fit a polynomial p of degree "degree" to the (x,y) data:
degree = 2;
p = polyfit(x,y,degree);
% Evaluate the fitted polynomial p and plot:
f = polyval(p,x);
eqn = sprintf('%f*Year^2+%f*Year+%f\n',p);
Rsquared = my_Rsquared_coeff(y,f); % correlation coefficient
figure(3);plot(x,y,'o',x,f,'-')
legend('data',eqn)
title(['Data fit - R squared = ' num2str(Rsquared)]);
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
function Rsquared = my_Rsquared_coeff(data,data_fit)
% R2 correlation coefficient computation
% The total sum of squares
sum_of_squares = sum((data-mean(data)).^2);
% The sum of squares of residuals, also called the residual sum of squares:
sum_of_squares_of_residuals = sum((data-data_fit).^2);
% definition of the coefficient of correlation is
Rsquared = 1 - sum_of_squares_of_residuals/sum_of_squares;
end
Steven Lord
Steven Lord 2021-12-14
fprintf lets you automatically include the sign of the variable if you include the flag + in your format specifier. The leading + in the result is a little awkward looking, but the command itself is quite simple and you could post-process the string to trim a leading + and to replace x^1 and x^0 with x and nothing if desired.
coeffs = [3 -4 5];
powers = 2:-1:0;
s = sprintf('%+dx^%d', [coeffs; powers])
s = '+3x^2-4x^1+5x^0'
if s(1) == '+'
s = s(2:end);
end
s = replace(s, 'x^1', 'x');
s = replace(s, 'x^0', '')
s = '3x^2-4x+5'

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更多回答(1 个)

KSSV
KSSV 2021-12-14
fprintf('%f*Year^2+%f*YEar+%f\n',pf)

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