curve generation plot for given pdf

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Kundan Prasad
Kundan Prasad 2021-12-14
评论： Kundan Prasad 2021-12-15
I am not able to generate the curve of FIg.5 as per attached pdf or given link below
file:///C:/Users/kp/OneDrive/Desktop/yang2017.pdf
I am trying to replicate the same but having some problem. Please solve the same
Thank you
clear all
clc
for i=1:2
alpha(i)= (pi*22)/180;
beta(i)= atan(cos(alpha(i))*sin(gamma(i))./(1+sin(alpha(i))*sin(gamma(i))));
end
R=0.4;
t(1)= R*cos(alpha(1))./cot(alpha(1)+beta(1));
t(2)= R*cos(alpha(2))./cot(alpha(2)+beta(2));
n_1=1.49;
theta_1= asin(n_1.*sin(alpha(1)))-alpha(1);
T=0.2;
H_1=0.1;
t(3)= (H_1-t(1)*(tan(alpha(1))-cot(theta_1)))./(cot(theta_1)-tan(alpha(2)));
t(4)= (t(2)*(tan(alpha(2))-cot(theta_1))+.....
T*(tan(alpha(1))-tan(alpha(2)))-H_1)./(tan(alpha(1))-cot(theta_1));
h_1=(T-t(1)-t(4))*tan(alpha(1));
h_2=(T-t(3)-t(2))*tan(alpha(2));
n_2=1.49;
lamda_min=0.004;
lamda_max=0.007;
phase= h_1*(n_1 -1)./(lamda_min)+ h_2*(n_2-1)./(lamda_min);
e1= (sin(pi*((1-(phase/2*pi))))/(pi*((1-(phase/2*pi)))))^2;
e2= (sin(pi*(t(1)/T))/(pi*(t(1)/T)))^2;
e3= (sin(pi*(t(2)/T))/(pi*(t(2)/T)))^2;
e4= (sin(pi*(t(3)/T))/(pi*(t(3)/T)))^2;
e5= (sin(pi*(t(4)/T))/(pi*(t(4)/T)))^2;
x=0.001;
f=0.025;
syms x
b= int(R-sqrt(R.^2-x.^2),0, f);
c=sqrt((1/f)*b);
e6= exp(((-4*pi*c)/lamda_min).^8);
effic= e1*e2*e3*e4*e5*e6;
syms lamda
pide=int(e1*e2*e3*e4*e5, lamda_min,lamda_max);
fpide= (1/(lamda_max-lamda_min))*pide;
  1 个评论
Kundan Prasad
Kundan Prasad 2021-12-15
please have a look into matlab code once.
I have attached the image of plot which is need to be obtained
Thank you

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