Cycle counter with reset

Question

0 个投票

I apologize for not having developed any code for this part, because I have no idea how to do it. So, I'm going to work with the block diagram and what I've created so far.

I can't think of a way to do this:

Basically, when p_fix is found it is to check if PE>p_fix every 5 cycles repeatedly until IC occurs. If PE>p_fix is not respected during these 5 cycles, it is to evaluate 5 cycles again and again....

What has been programmed so far:

for n = 1:size(t,1)
     if  n>=4
         X = [Ia(n-1,1) Ia(n-2,1) ; Ia(n-2,1) Ia(n-3,1)];
         future = [Ia(n,1) ; Ia(n-1,1)];
         C = X\future;
         Ia_future(n,1) = C(1,1)*Ia(n,1)+C(2,1)*Ia(n-1,1);
         PE(n,1)=Ia(n,1)+Ia_future(n,1);
         p(n,1) = (1+0.2)*max(PE);
         
     if  PE(n,1)>p(n,1)
         p_fix = p(n,1);
      
             
                
         end
     end
 end