how can I plot a game board in a figure

Question

Tariq Hammoudeh 2021-12-19

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1614260-how-can-i-plot-a-game-board-in-a-figure

评论： Walter Roberson 2021-12-23

Im programming the game battleship, and i need create a figure 2, 6 by 6 boards (one for the user and one for the computer). I was searching up on figures in matlab but i didnt find anything on how to create a grid in the figure. So how can i do that please, also can i have each grid correspond to a number from 1 to 36.

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Answer 1

Image Analyst 2021-12-19

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1614260-how-can-i-plot-a-game-board-in-a-figure#answer_858430

在 MATLAB Online 中打开

You can just do

numSpaces = 6;

myBoard = zeros(numSpaces+1,numSpaces+1);

computersBoard = zeros(numSpaces+1,numSpaces+1);

subplot(1, 2, 1);

pcolor(myBoard);

axis square

title('Your Board', 'FontSize', 15)

subplot(1, 2, 2);

pcolor(computersBoard);

axis square

title('Computer Board', 'FontSize', 15)

Check the File Exchange, and click the tag on the left for numerous battleship programs:

https://www.mathworks.com/matlabcentral/answers/?term=tag%3A%22battleship%22

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Image Analyst 2021-12-19

在 MATLAB Online 中打开

Try this:

% Demo by Image Analyst, December, 2021.
clc;    % Clear the command window.
close all;  % Close all figures (except those of imtool.)
clearvars;
workspace;  % Make sure the workspace panel is showing.
format long g;
format compact;
fontSize = 16;
fprintf('Beginning to run %s.m ...\n', mfilename);
numSpaces = 6;
myBoard = zeros(numSpaces+1,numSpaces+1);
computersBoard = zeros(numSpaces+1,numSpaces+1);
%-----------------------------------------------------------------------
% YOUR BOARD.
subplot(1, 2, 1);
pcolor(myBoard);
colormap([1,1,1])
axis square
title('Your Board', 'FontSize', 15)
% Set up the outside tick labels.
xticks(0.5 : numSpaces + 0.5)
xtl = {'0', '1', '2', '3', '4', '5', '6'};
xticklabels(xtl)
yticks(0.5 : numSpaces + 0.5)
ytl = {'0', 'F', 'E', 'D', 'C', 'B', 'A'};
yticklabels(ytl)
% Put up grid locations in the cells.
for row = 1 : numSpaces
    for col = 1 : numSpaces
        str = sprintf('%s%s', ytl{col + 1}, xtl{row + 1});
        xt = row + 0.5;
        yt = col + 0.5;
        text(xt, yt, str, 'Color', 'r', 'FontSize', 8, 'FontWeight','bold', 'HorizontalAlignment','center')
    end
end
%-----------------------------------------------------------------------
% COMPUTER'S BOARD.
subplot(1, 2, 2);
pcolor(computersBoard);
axis square
title('Computer Board', 'FontSize', 15)
% Set up the outside tick labels.
xticks(0.5 : numSpaces + 0.5)
xticklabels(xtl)
yticks(0.5 : numSpaces + 0.5)
yticklabels(ytl)
% Put up grid locations in the cells.
for row = 1 : numSpaces
    for col = 1 : numSpaces
        str = sprintf('%s%s', ytl{col + 1}, xtl{row + 1});
        xt = row + 0.5;
        yt = col + 0.5;
        text(xt, yt, str, 'Color', 'r', 'FontSize', 8, 'FontWeight','bold', 'HorizontalAlignment','center')
    end
end

Image Analyst 2021-12-19

编辑：Image Analyst 2021-12-19

在 MATLAB Online 中打开

Of course you can. Please try to program it up. You learn by doing.

If the code below works, please Accept the answer. Thanks in advance 🙂

% Demo by Image Analyst, December, 2021.
clc;    % Clear the command window.
close all;  % Close all figures (except those of imtool.)
clearvars;
workspace;  % Make sure the workspace panel is showing.
format long g;
format compact;
fontSize = 16;
fprintf('Beginning to run %s.m ...\n', mfilename);
numSpaces = 6;
myBoard = zeros(numSpaces+1,numSpaces+1);
computersBoard = zeros(numSpaces+1,numSpaces+1);
%-----------------------------------------------------------------------
% YOUR BOARD.
subplot(1, 2, 1);
pcolor(myBoard);
colormap([1,1,1])
axis square
title('Your Board', 'FontSize', 15)
% Set up the outside tick labels.
xticks(0.5 : numSpaces + 0.5)
xtl = {'0', '1', '2', '3', '4', '5', '6'};
xticklabels(xtl)
yticks(0.5 : numSpaces + 0.5)
ytl = {'0', 'F', 'E', 'D', 'C', 'B', 'A'};
yticklabels(ytl)
% Put up grid locations in the cells.
counter = 1;
for row = 1 : numSpaces
	for col = 1 : numSpaces
		str = sprintf('%d', counter);
		xt = row + 0.5;
		yt = numSpaces - col + 1.5;
		text(xt, yt, str, 'Color', 'r', 'FontSize', 8, 'FontWeight','bold', 'HorizontalAlignment','center')
		counter = counter + 1;
	end
end
%-----------------------------------------------------------------------
% COMPUTER'S BOARD.
subplot(1, 2, 2);
pcolor(computersBoard);
axis square
title('Computer Board', 'FontSize', 15)
% Set up the outside tick labels.
xticks(0.5 : numSpaces + 0.5)
xticklabels(xtl)
yticks(0.5 : numSpaces + 0.5)
yticklabels(ytl)
% Put up grid locations in the cells.
% This has the numbers going in the opposite direction.
counter = 1;
for col = 1 : numSpaces
	for row = 1 : numSpaces
		str = sprintf('%d', counter);
		xt = row + 0.5;
		yt = numSpaces - col + 1.5;
		text(xt, yt, str, 'Color', 'r', 'FontSize', 8, 'FontWeight','bold', 'HorizontalAlignment','center')
		counter = counter + 1;
	end
end

Pick whichever direction for the numbers you want.

Walter Roberson 2021-12-21

在 MATLAB Online 中打开

Nothing in the code that Image Analyst posted deliberately opens a new figure.

In the posted code, what could potentially open a new figure is the call

subplot(1, 2, 1);

if there is no "traditional" figure at all, that code would cause one to be created
if there are traditional figures, but none of them are marked internally as the "current figure", then that line of code would result in a new traditional figure being opened. Usually it is not enough to delete the current figure in order to cause the "current figure" to be set empty: in such a case, the current figure is usually selected from the children of the graphics root. However, figures would not be eligible for automatic selection if the figure handlevisibility property is set "off" or (sometimes) "callback". Also, if the graphics root CurrentFigure property is deliberately set to empty, then no other figure will be substituted when a figure is closed.

Pay attention here to where I said "traditiona figure": if you happen to be using App Designer, then that subplot() call is likely to cause a new figure to be created. If you are using App Designer then all of the graphics operations in the code must be changed to refer to the appropriate parent graphics object. For example,

hold(app.axis1, 'on')

instead of hold on

Tariq Hammoudeh 2021-12-21

编辑：Walter Roberson 2021-12-21

在 MATLAB Online 中打开

Thank you for that, but i tried this instead of the other code and i would get "Unrecognized function or variable 'first_time'.".

But the other code works fine, its just that i need to write if statements, so,

startingGrid= input('please enter the number of the grid you want your ship to start in')
if startingGrid == 1
change the color of grids numbers 1 and 2
end

Is that possible in code, to choose specifc number of the grid to another color to represesnt ships, using image analyst's code:

 numSpaces = 6;  % to plot a gridded figure with 6 rows and 6 columns
        playersBoard = zeros(numSpaces+1,numSpaces+1);
        computersBoard = zeros(numSpaces+1,numSpaces+1);
         %Creating the player's boards
        subplot(2, 1, 2);
         pcolor(playersBoard);
         colormap([1,1,1])
         axis square  % to make the plot have grids
         title('Your Board', 'FontSize', 15) %setting up the title of the board with the size of the text
         axis off;
         % Putting the numbers in each grid, using a for loop to put a number
         % in each grid and move on to the next.
         count = 1;
         for col = 1 : numSpaces
             for row = 1 : numSpaces
                 str = sprintf('%d', count);
                 xt = row + 0.5;
                 yt = numSpaces - col + 1.5;
                 text(xt, yt, str, 'Color', 'r', 'FontSize', 8, 'FontWeight','bold', 'HorizontalAlignment','center')
                 count = count + 1;
             end
         end

Walter Roberson 2021-12-21

编辑：Walter Roberson 2021-12-21

在 MATLAB Online 中打开

numSpaces = 6;  % to plot a gridded figure with 6 rows and 6 columns
playersBoard = zeros(numSpaces+1,numSpaces+1);
computersBoard = zeros(numSpaces+1,numSpaces+1);
%Creating the player's boards
subplot(2, 1, 2);
user_board = pcolor(playersBoard);
colormap([1,1,1; 1 0 0; 0 0 1; 0 0 0]);  %white for unknown, red for player 1, blue for player 2, black for known empty
axis square  % to make the plot have grids
title('Your Board', 'FontSize', 15) %setting up the title of the board with the size of the text
axis off;
% Putting the numbers in each grid, using a for loop to put a number
% in each grid and move on to the next.
count = 1;
for col = 1 : numSpaces
    for row = 1 : numSpaces
     str = sprintf('%d', count);
     xt = row + 0.5;
     yt = numSpaces - col + 1.5;
     text(xt, yt, str, 'Color', 'r', 'FontSize', 8, 'FontWeight','bold', 'HorizontalAlignment','center')
     count = count + 1;
    end
end
while true
    startingGrid = input('please enter the number of the grid you want your ship to start in');
    if ~isscalar(startingGrid) || ~isnumeric(startingGrid) || ...
            startingGrid < 1 | startingGrid > numSpaces || ...
            startingGrid ~= floor(startingGrid)
       fprintf('Must be integer from 1 to %d\n', numSpaces);
    else
        break
    end
end
orientation = randi(2);
if orientation == 1
    row = randi(numSpaces);
    col = randi(numSpaces-startingGrid);
    playersBoard(row, col:col+startingGrid-1) = 1;
else
    row = randi(numSpaces-startingGrid);
    col = randi(numSpaces);
    playersBoard(row:row+startingGrid-1, col) = 1;
end
user_board.CData = playersBoard;
drawnow;

Walter Roberson 2021-12-21

编辑：Walter Roberson 2021-12-21

在 MATLAB Online 中打开

while true
    aim_row = input('Please enter row to aim for: ');
    if ~isscalar(aim_row) || ~isnumeric(aim_row) || ...
            aim_row < 1 | aim_row > numSpaces || ...
            aim_row ~= floor(aim_row)
       fprintf('Must be integer from 1 to %d\n', numSpaces);
    else
        break
    end
end
while true
    aim_col = input('Please enter column to aim for: ');
    if ~isscalar(aim_col) || ~isnumeric(aim_col) || ...
            aim_col < 1 | aim_col > numSpaces || ...
            aim_col ~= floor(aim_col)
       fprintf('Must be integer from 1 to %d\n', numSpaces);
    else
        break
    end
end
what_is_there = player2Board(aim_row, aim_col);
if what_is_there == 0
   playerBoard(aim_row, aim_col) = 3;
elseif what_is_there == 1
    fprintf('Your opponent has one of your pieces?!?!\n');
    playerBoard(aim_row, aim_col) = 3;
elseif what_is_there == 2
    playerBoard(aim_row, aim_col) = 2;
    fprintf('You hit!!\n');
elseif what_is_there == 3
    fprintf('You already aimed there!\n');
end
user_board.CData = playerBoard;

Tariq Hammoudeh 2021-12-21

在 MATLAB Online 中打开

Thank you for that, but firslty this code just removed the computer's board (when I run it, it only shows the player's board and its all in blue) and only colors 1 grid after inputting the starting grid. Also I need the player to be able to place his 5 ships using, the startingGrid then whether its vertical or horizonatal,

I had this in mind:

disp(' Its time to place your ships')
        disp(' You will now place your corvette (1X2) ship')
        startingGrid= input(' Please choose the grid number you want your ship to start in : ');
orientation= input( please enter v if you want your ship to be placed vertically, or h if you want your ship to be placed horizontally)
if startingGrid == 1
if orientation == v
change grids 1 and 7 to blue
elseif orientation == h
change grids 1 and 2 to blue
end
end

Because i need to be able to place 5 different ships each with different dimensions,

Also im very well aware that this way is not practical at all as ill need to have 36 if statements for each of the 5 ships, but it is the only way i can think of. So how can i make it so that the player can just enter the starting grid then orientation, then the correct number of grids change color, while keeping the computer's boards in the figure.

Walter Roberson 2021-12-22

is there a way to also a set colored grid (ship placed in grid) as full

NO, there is not.

You need two graphics objects, one showing the user's board as the user knows it (the one that is "hidden" from the opponent), and the other one showing the opponent's board as the user knows it, which should start showing no information known.

You are effectively asking whether you could get away with just having the graphics two graphics object, and checking one of them to see whether the position the user aimed at was occupied. But the graphics object that displays what the user knows about the opponent's board does not know what the opponent has at a given location unless that information has already been revealed by the user having already aimed there.

You also need an array representing the current state of the user's board (as known to the user), and another array representing the current state of the opponent's board (as known to the user), and another array representing the current state of the opponent's board (as known to the opponent), and another array representing the current state of the user's board (as known to the opponent.)

In the code I posted, I only used two arrays, one representing what the user knows, and one representing what the opponent knows. That was a mistake on my part, as it does not easily allow information about the opponents board to be represented in the same square as information about the user's pieces. For example of the user had a piece at C4 and aimed the opponent's C4 and found the opponent was empty there, then you need information for C4 that the user has a piece and that the user has checked and found the opponent's space empty at C4. Easiest to separate into two arrays. It is, though, not the only way -- you can encode information about both players, if you are willing to do a bit more work extracting the information.

For that matter, it would be possible to encode all of the information in one array:

0 -- not occupied by either player and neither player has fired at the other player there
1 -- occupied by the player only and neither player has fired at the other player there
2 -- occupied by the opponent only and neither player as fired at the other player there
3 -- occupied by the player and the opponent and neither player has fired at the other player there
4 -- not occupied by either player and the player has fired at the opponent there -- a miss for the player
5 -- occupied by the player only and the player has fired at the opponent there -- a miss for the player
6 - occupied by the opponent only and the player has fired at the opponent there -- a hit for the player
7 occupied by the player and the opponent and the player has fired at the opponent there -- a hit for the player
8 not occupied by either player, and the opponent has fired at the player here -- a miss for the opponent
9 occupied by the player only and the opponent has fired at the player here -- a hit for the opponent
10 occupied by the opponent only and the opponent has fired at the player here -- a miss for the opponent
11 occupied by the player and the opponent and the opponent has fired at the player here -- a hit for the opponent
12 not occupied by either player and the player has fired at the opponent here and the opponent has fired at the player here -- a miss for the player and a miss for the opponent
13 occupied by the player only and the player has fired at the opponent there and the opponent has fired at the player there -- a miss for the player but a hit for the opponent
14 occupied by the opponent only and the player has fired at the opponent there and the opponent has fired by the player there -- a hit for the player and a miss for the opponent
15 occupied by the player and the opponent and both have fired at each other there -- a hit for the player and a hit for the opponent

So you could encode everything into one array, and then process it to figure out what to display. If you think that is easier.

Walter Roberson 2021-12-22

在 MATLAB Online 中打开

In that case, the answer to

is there a way to also a set colored grid (ship placed in grid) as full

is:

If you have saved the handle to the pcolor() object that was used to display the user's board as known to the user, and the opponent (the computer) is aiming at the human player, then you can

grid_is_full = graphics_object_for_user_board.CData(IndexAimedAt);
if grid_is_full
   disp('Computer hit!');
   graphics_object_for_user_board.CData(IndexAimedAt) = 2;  %it's been hit
else
    disp('Computer missed!');
end

However, there is no graphics object representing where the computer stored its pieces, so you cannot use the same technique to determine whether the user was successful in hitting the computer's pieces. Instead, you would have to consult an array of data that is not a graphics object.

Eventually, you would have something like

grid_is_full = array_for_computer_board(IndexAimedAt);
if grid_is_full
   disp('Player hit!');
   graphics_object_for_computer_board.CData(IndexAimedAt) = 2;  %it's been hit
else
   disp('Player missed!');
   graphics_object_for_computer_board.CData(IndexAimedAt) = 1;  %it's been missed, but it is no longer unknown
end
drawnow()

Walter Roberson 2021-12-23

http://www.mathworks.com/matlabcentral/answers/8026-best-way-s-to-master-matlab

There is a difference between not knowing which routines to call to accomplish tasks, compared to saying that you can't learn if you do not already have code for the same purpose in front of you.

There are lots and lots of example programs in the File Exchange, and if you ask us about specific tasks then we are happy to answer.

But you have effectively told us that you need us to write the whole program for you first before you can write your own code, and we are not willing to write the whole program for you.

I have shown you how to change specific locations in graphics by altering the CData property of the handle returned by pcolor()

I have shown you how to make tests of whether conditions are satisfied or not.

Additional hints:

pcolor() is the wrong thing to use. Use image() instead -- but make sure the data values are uint8() so that the data values can act like images into the color map (I already showed you an example of a color map)
input() with only a prompt always executes the line that the user types as if it were code. So if you ask the user to enter h or v and they enter those, then MATLAB would attempt to execute the v or p, by searching for variables and functions with those names. If you want the user to enter text then add the 's' option to input()
Use strcmp() to compare text. For example strcmp(orientation, 'v')
You will find that it is easier to have the user enter positions in terms of grid coordinates. In classic Battleships game the rows are numbered 1 to 10 and the columns are labeled 'A' to 'J' . If you have the user enter the coordinates as text you could figure out whether they had entered number-letter or letter-number and extract appropriate parts.
The reason it is easier with grid coordinates than with numbers like 1 to 36, besides being easier for the user to understand, is that when you want to place a ship, it is easiest to have row and column of the starting point so that you can use (row, column:column+length-1) or (row:row+length-1,column) like I showed in https://www.mathworks.com/matlabcentral/answers/1614260-how-can-i-plot-a-game-board-in-a-figure#comment_1899030

Image Analyst 2021-12-23

Yes I agree that image() would be better than pcolor(). The only disadvantage is that image() doesn't give grid lines while pcolor() does. However you can use yline() and xline() to draw grid lines. If you do that then image is probably better because with pcolor you need to have one more row and column of your matrix that you basically don't use because pcolor() does not display the last row and column of the matrix.