function doesnt works well

2021 12 20
2 个回答
更新时间：2021 12 21
5 次查看（30 天）

0 个投票

Hi, I am using this function;
function [s,tint] = spei(t,prec,pevap,varargin)
But, I am not sure what is varargin works for?
The size of my file are;
t=1x1x420
prec=98x56x420
pevap=98x56x420
Error using spei (line 40)
Expected a string scalar or character vector for the parameter name.

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Star Strider
Star Strider 2021-12-20
It will be necessary to carefully read the documentation for the file to understand what the arguments must be, and what their order must be.
Rik
Rik 2021-12-20
Function posted in duplicate question:
function [spei_index]=calculate_spei(t,prec,pevap,varargin);
[nlon, nlat, n]=size(prec);
prec=squeeze(prec);
for i=1:nlon
for j=1:nlat
if isnan(prec(i,j,1))==0
spei_index(i,j,:)=spei(t,prec(i,j,:),pevap(i,j,:),varargin);
else
spei_index(i,j,:)=ones(1,n-12)*NaN;
end
end
end

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回答（2 个）

Walter Roberson
Walter Roberson 2021-12-20

1 个投票

spei_index(i,j,:) = spei(t, prec(i,j,:), pevap(i,j,:), varargin{:} );
is my guess.

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Rik
Rik 2021-12-21
Good catch, I should have spotted this. I'll leave my answer up for documentary purposes.
I can use this function on vector,
s = spei(t',prec,pevap);
prec=420x1
pevap=420x1
but, i need to do a loop for a prec=58x69x420 right?
Walter Roberson
Walter Roberson 2021-12-21
No, that is not needed. The documentation states
% s = spei(t,prec,pevap) computes the standardised precipitation-evapotranspiration
% index s, given precipitation prec and potential evaporation pevap corresponding
% to times t. prec and pevap can be either be 1D vectors or 3D cubes, whose
% first two dimensions are spatial and whose third dimension corresponds to times
% t. The dimensions of prec and pevap must agree. Times t can be datetime
% or datenum format.
so passing in a vector of times of length 420 is fine if your prec and pevap are something by something by 420.
so it should be okay right if my data:
prec=98x56x420
pevap=98x56x420
and
t=1x420
but, this is my error
Error using rect2cube (line 46)
Error: Dimensions of the gridsize must match the number of columns in A2.
Error in spei (line 117)
s = rect2cube(s,gridsize);

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Rik
Rik 2021-12-20
Ran in:

0 个投票

Ran in:
varargin is typically used to capture optional input arguments:
help varargin
VARARGIN Variable length input argument list. Allows any number of arguments to a function. The variable VARARGIN is a cell array containing the optional arguments to the function. VARARGIN must be declared as the last input argument and collects all the inputs from that point onwards. In the declaration, VARARGIN must be lowercase (i.e., varargin). For example, the function, function myplot(x,varargin) plot(x,varargin{:}) collects all the inputs starting with the second input into the variable "varargin". MYPLOT uses the comma-separated list syntax varargin{:} to pass the optional parameters to plot. The call, myplot(sin(0:.1:1),'color',[.5 .7 .3],'linestyle',':') results in varargin being a 1-by-4 cell array containing the values 'color', [.5 .7 .3], 'linestyle', and ':'. See also VARARGOUT, NARGIN, NARGOUT, INPUTNAME, FUNCTION, LISTS, PAREN. Documentation for varargin doc varargin
Since you don't use the optional/unnamed inputs, there shouldn't be any issues.
The function you're using should have documentation explaining how to use it. Read it. If you don't understand it, please provide a reference to where you got this function (as I can't find it).

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I got the function from here.
I don't really understand it.
Walter Roberson
Walter Roberson 2021-12-21
In that case my suggestion was correct.

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