Convert 385360 cell array containing 133 vector into 1360 Matrix containing 38533 double

Question

Johanna Popp 2021-12-22

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1616130-convert-385-360-cell-array-containing-1-33-vector-into-1-360-matrix-containing-385-33-double

评论： Johanna Popp 2021-12-22

Hi all,

I am trying to convert 385*360 cell array, with each cell containing a 1*33 vector of double values, into a 1*360 cell array containing 385*33 double values. Here is the Code (+ Annotations) that I have so far but it doesn't seem to work the way I want it to.

Any help would be appreciated, thanks!!

for i = 1:385
    for j = 1:360
        x = Node_all{i,j} % Node_all is the Matrix size 385*360 containing 1*33 double each 
        Node_complete(i,:) = x % This is the Information from each collumn summed up in 1 Matrix (385 *33)
        
        All_Nodes_complete{j,1} = Node_complete % Now trying to put the 385*33 Matrix back into a cell (1*360)
    end
end

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Answer 1

Voss 2021-12-22

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1616130-convert-385-360-cell-array-containing-1-33-vector-into-1-360-matrix-containing-385-33-double#answer_860305

在 MATLAB Online 中打开

Here is one way to do it:

n = size(Node_all,2);
All_Nodes_complete = cell(1,n);
for j = 1:n
    All_Nodes_complete{j} = vertcat(Node_all{:,j});
end

Or another way (more like the way you were trying):

[m,n] = size(Node_all);
for j = 1:n
    for i = 1:m
%         x = Node_all{i,j}; % Node_all is the Matrix size 385*360 containing 1*33 double each 
%         Node_complete(i,:) = x; % This is the Information from each collumn summed up in 1 Matrix (385 *33)
        Node_complete(i,:) = Node_all{i,j};
    end
    All_Nodes_complete{1,j} = Node_complete; % Now trying to put the 385*33 Matrix back into a cell (1*360)
end