Coding Euler's Method!!
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Hello everyone so I am trying to code Euler's method to solve this matrix A and I can't figure it out. Here is my code so far:
k_AB = 0.4;
k_BC = 0.1;
k_CA = 0.4;
k_ba = 0.2;
k_cb = 0.45;
k_ac = 0.16;
A = [ (-k_AB - k_ac), k_ba, k_CA;
k_AB, (-k_BC - k_ba), k_cb;
k_ac, k_BC, (-k_CA - k_cb); ];
x0 = [1;0;0];
h = 0.1;
for t = 0:0.1:1
xNEW = x0 + h*(A*x0);
x0 = xNEW
end
x0 = [2;0;0];
It seems that my first step has the 3 correct values, but every step after that is incorrect. If anyone who is familiar with Euler's Explicit Method can help I'd be extremely grateful! I've been trying this for hours on my Friday night :(
So step size = 0.1, initial conditions = [1;0;0] from time interval 0:0.1:1
Any help works!
3 个评论
James Tursa
2014-11-8
Why do you think other steps are incorrect? Are all the elements correct with the derivative matrix A?
Sharif
2014-11-8
Sharif
2014-11-9
采纳的回答
Mohammad Abouali
2014-11-9
Your code is correct. What is x0 = [2;0;0]; at the end though.
Here is a modified version of your code. It is modified in such a way that you plot the changes in time at the end for each element of x
clear;
clc;
close all;
k_AB = 0.4;
k_BC = 0.1;
k_CA = 0.4;
k_ba = 0.2;
k_cb = 0.45;
k_ac = 0.16;
A = [ (-k_AB - k_ac), k_ba, k_CA;
k_AB, (-k_BC - k_ba), k_cb;
k_ac, k_BC, (-k_CA - k_cb); ];
x(:,1) = [1;0;0];
h = 0.1;
t=0:h:1;
for i=2:numel(t)
x(:,i) = x(:,i-1) + h*(A*x(:,i-1));
end
plot(t,x(1,:),'b')
hold on
plot(t,x(2,:),'r')
plot(t,x(3,:),'k')
xlabel('Time')
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