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Finding Rise Time from System Response

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Philip Asante-Mireku
编辑： Philip Asante-Mireku 2021-12-29
Ran in:
I am trying to find appropriate sample time from the open loop response from my system for use in model predictive control:
A=[-1 1.6 0;0 0 1;0 0 -11.76];
B=[0; 0; 1];
C=[50 0 0];
D=zeros(1,1);
Cont_plant=ss(A,B,C,D); %continuous state space dynamics of plant
step(Cont_plant)
How do i get get the rise time,settling time since this system is not open loop stable? I tried to put it in feedback and still this:
A=[-1 1.6 0;0 0 1;0 0 -11.76];
B=[0; 0; 1];
C=[50 0 0];
D=zeros(1,1);
Cont_plant=ss(A,B,C,D); %continuous state space dynamics of plant
step(Cont_plant)
G=feedback(Cont_plant,1)
G = A = x1 x2 x3 x1 -1 1.6 0 x2 0 0 1 x3 -50 0 -11.76 B = u1 x1 0 x2 0 x3 1 C = x1 x2 x3 y1 50 0 0 D = u1 y1 0 Continuous-time state-space model.
step(G)

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回答（1 个）

Burhan Burak AKMAN
Burhan Burak AKMAN 2021-12-29
Ran in:
You can use 'stepinfo' function like below.
A=[-1 1.6 0;0 0 1;0 0 -11.76];
B=[0; 0; 1];
C=[50 0 0];
D=zeros(1,1);
Cont_plant=ss(A,B,C,D); %continuous state space dynamics of plant
step(Cont_plant)
G=feedback(Cont_plant,1);
step(G)
stepinfo(G)
ans = struct with fields:
RiseTime: 0.4450 TransientTime: 17.6458 SettlingTime: 17.6458 SettlingMin: 0.4255 SettlingMax: 1.7478 Overshoot: 74.7832 Undershoot: 0 Peak: 1.7478 PeakTime: 1.3568
  1 个评论
Philip Asante-Mireku
Philip Asante-Mireku 2021-12-29
编辑：Philip Asante-Mireku 2021-12-29
Is the closed loop response rise time appropriate for use in Model Predictive control for finding prediction horizon and control horizon?

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