can someone help me in coding hash 512 algorithm?

Question

yogya 2014-11-9

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/161979-can-someone-help-me-in-coding-hash-512-algorithm

评论： Jan 2014-11-9

hello i need a hash value that provide me as decimal value from 512 bits binary value. can someone please correct my code and help me. Where my code is

data = input('enter the data:','s');
pawrd = input('enter the password:','s');
bin = double(data);
display(bin);
n = dec2base(bin,16);
display(n);
len_n = length(n);
display(len_n);
k = dec2bin(bin,8);
display(k);
pwd = dec2bin(pawrd,8)';
pwd = pwd(:)'-'0';
ln_pwd = length(pwd);
disp(ln_pwd);
pad_pwd = [pwd , ones(1,64-ln_pwd)];
A = dec2bin(data,8)';
A = A(:)'-'0';
le_a = length(A); 
pad2 = dec2bin(le_a,8)';
pad2 = pad2(:)'-'0';
j = length(pad2);
dap2 = [zeros(1,128-j), pad2];
display(pad2);
display(A);
display(le_a);
x = 896-le_a;
display(x);
if  x == 0
    display('seq need not to be padded');
else
    padarray = [ones(1,1), zeros(1,x-1)];
    paddedseq  = [A, padarray];
    finalpad = [paddedseq, dap2];
    l_paddedseq = length(finalpad);
    display(l_paddedseq);
    display(paddedseq);
    display(finalpad);
  x1 = '6A09E667F3BCC908';
  x2 = 'BB67AE8584CAA73B';
  x3 = '3C6EF372FE94F82B';
  x4 = 'A54FF53A5F1D36F1';
  x5 = '510E527FADE682D1';
  x6 = '9B05688C2B3E6C1F';
  x7 = '1F83D9ABFB41BD6B';
  x8 = '5BE0CD19137E2179';
bx1 = base2dec(x1,16); 
bx2 = base2dec(x2,16); 
bx3 = base2dec(x3,16); 
bx4 = base2dec(x4,16);
bx5 = base2dec(x5,16);
bx6 = base2dec(x6,16);
bx7 = base2dec(x7,16);
bx8 = base2dec(x8,16);
a = dec2bin(bx1,64);
display(a);
b = dec2bin(bx2,64);
display(b);
c = dec2bin(bx3,64);
display(c);
d = dec2bin(bx4,64);
display(d);
e = dec2bin(bx5,64);
display(e);
f = dec2bin(bx6,64);
display(f);
g = dec2bin(bx7,64);
display(g);
h = dec2bin(bx8,64);
display(h);
end
    w =reshape(finalpad,16,64);
    display(w);
          wi = w(i, 1:64);
          disp(wi);
          ki = circshift(pad_pwd,1);
          disp(ki);
          and1 = e&f;
      and2 = (~e)&g;
      and3 = a&b;
      and4 = a&c;
      and5 = b&c;
      Ch = bitxor(and1,and2);
      display(and1);
      display(and2);
      display(Ch);
      Maj1 = bitxor(and3,and4);
      display(Maj1);
      maj = bitxor(Maj1,and5);
      display(maj);  
  r1 = circshift(e,[0  +14])-'0' ;
  disp(r1);
  r2 = circshift(e,[0  +18])-'0';
  disp(r2);
  r3 = circshift(e,[0  +41])-'0';
  r4 = circshift(a,[0  +28])-'0';
  r5 = circshift(a,[0  +34])-'0';
  r6 = circshift(a,[0  +39])-'0';
  r12 = bitxor(r1,r2);
  r45 = bitxor(r4,r5);
  sum1e = bitxor(r12,r3);
  sum0a = bitxor(r45,r6);
  T1 = h|Ch|wi|ki|sum1e;
  disp(T1);
  T2 = maj|sum0a;
  disp(T2);
  h = g;
  disp(h);
  g = f;
  disp(g);
  f = e;
  disp(f);
  e = d|T1;
  disp(e);
  d = c;
  disp(d);
  c = b;
  disp(c);
  b = a;
  disp(b);
  a = T1|T2;
  disp(a);
  a=a(a~='0');
     disp(a);