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PCOLOR command in Matlab App Designer

11 次查看（过去 30 天）
Michal Cerny
Michal Cerny 2022-1-2
评论： Image Analyst 2022-1-2
I have achieved working and running code in Matlab, but I have problem converting it for use in the App Designer. I am mostly struggling with the syntax. For the graph I am using UIAxes in app designer.
the code:
E=[1 1 0 0 1 0;1 1 0 0 1 0;1 1 0 0 1 0;1 1 0 0 1 0;1 1 0 0 1 0;1 1 0 0 1 0;]
grid=pcolor(padarray(E,[1 1],'replicate','post'))
grid.EdgeColor=[0 0 0]
grid.LineWidth=3
colormap(jet(4))
set(gca,'ydir','reverse')
axis equal
Thank you very much for your help
Michal Cerny

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采纳的回答

Walter Roberson
Walter Roberson 2022-1-2
Instead of passing the uiaxes as the first parameter, use the 'Parent' name/value pair.
grid = pcolor(padarray(E,[1 1],'replicate','post'), ...
'Parent', app.UIAxes, 'EdgeColor', [0 0 0], 'LineWidth', 3);
colormap(app.UIAxes, jet(4))
app.UIAxes.YDir = 'reverse';
axis(app.UIAxes, 'equal')
  2 个评论
Michal Cerny
Michal Cerny 2022-1-2
Error using pcolor (line 50)
Too many input arguments.
--------------------------------
Thank you for help. For some reason it still gives the error above. There is no other "pcolor" command used anywhere in the code.
--------------------------------
Image Analyst
Image Analyst 2022-1-2
Ran in:
Try this:
E = rand(5,5); % Just for demo - you should delete this line.
app.UIAxes = axes(); % Just for demo - you should delete this line.
paddedE = padarray(E,[1 1],'replicate','post')
paddedE = 6×6
0.1886 0.4694 0.1405 0.3392 0.2175 0.2175 0.8035 0.1835 0.3030 0.5094 0.1928 0.1928 0.6563 0.1289 0.4795 0.6464 0.4215 0.4215 0.6175 0.4941 0.3259 0.2673 0.0400 0.0400 0.2382 0.3621 0.1431 0.6461 0.7562 0.7562 0.2382 0.3621 0.1431 0.6461 0.7562 0.7562
hp = pcolor(paddedE, 'Parent', app.UIAxes);
hp.EdgeColor = [0 0 0];
hp.LineWidth = 3;
colormap(app.UIAxes, jet(4))
app.UIAxes.YDir = 'reverse';
axis(app.UIAxes, 'equal')

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