print acsii characters in tabular format using char

Question

jarvan 2014-11-11

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/162176-print-acsii-characters-in-tabular-format-using-char

编辑： pietro 2014-11-11

I am writing a function that will receive a matrix of integers uint8 less than 129 as input agrument. And print it as acsii characters in tabular format using char

 function mychar(y)
if y > 129
    disp('Please enter less than 129.')
else
    x = char(uint8(y))
    table1 = uitable
    set(table1,'Data',x)
end

However, it said data must be a numeric, logic. Is that any codes I missed on above?

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Answer 1

pietro 2014-11-11

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/162176-print-acsii-characters-in-tabular-format-using-char#answer_158470

编辑：pietro 2014-11-11

在 MATLAB Online 中打开

try this:

   function mychar(y)
if y > 129
    disp('Please enter less than 129.')
else
    x = char(uint8(y))
    table1 = uitable
    set(table1,'Data',{x})
end