I am trying to write a function but it will not work.
4 次查看(过去 30 天)
显示 更早的评论
function [ absorption ] = solar_rad( nc,lat,t,I)
%Calculating absorbed solar radiation
% Calculating the absorbed solar radiaiton as a function of time of
% day and year, cloud cover, and latitude, using a time step of one hour.
%BEGIN
for I=1:365;
for T=[0:24];
t=T*3600;
end
delta=-23.45*(pi/180)*cosd(2*pi)/365*(I+9); %Declination
S=1357+45*cosd((2*pi)/365)*(I); %Solar constant
for lat=0;
sinh=max(sind(lat)*sind(delta)+cosd(lat)*cosd(delta)*cosd((2*pi/86400)*(t+43200)));
m=1/sinh; %optical length
Cext=0.128-0.0253*(log(m)); %Extinction
end
for h=asin(max(sind(lat)*sind(delta)+cosd(lat)*cosd(delta)*cosd((2*pi)/86400)*(t+43200)));
i=(pi/2)-h; %angle of incidence
j=asin(0.75*sin(i)); %angle of reflection
r=0.5*abs((sin(i-j)^2/sin(i+j)^2)+(tan(i-j)^2)/(tan(i+j)^2)); %reflectance
end
end
for nc=0:100;
if h>0
Insd=S*(exp(-Cext*m))*(sin(h))*(1-(0.71*nc)); %direct incoming solar radiation at sea level
end
if h<=0
Insd=0;
end
for Insg=0.52*nc*Insd; %global radiation
Q_sun=Insd*(1-r)+0.97*Insg;
end
end
[absorption]=solar_rad(0,0,t,I);
Whenever I run it I get this error message:
Error in solar_rad (line 7)
for I=1:365;
Output argument "absorption" (and maybe others) not assigned during call to "\\fs-home-k\home-005\osp42f\My
Documents\MATLAB\Programmes\solar_rad.m>solar_rad".
0 个评论
采纳的回答
Star Strider
2014-11-12
You don’t have any variable named ‘absorption’ on the left-hand side of any statement anywhere in your code for your ‘solar_rad’ function. It has to have a variable by that specific name assigned somewhere in your code or it will not return any value for that variable.
2 个评论
Star Strider
2014-11-12
I don’t understand what you mean by ‘a matrix joining I and T’. ‘T’ and ‘I’ are indices.
Also, I don’t understand what you’re doing here:
cosd(2*pi)
since the trig functions ending with ‘d’ take their arguments in degrees. Those without take their arguments in radians. In any event, cos(2*pi) will always evaluate to 1, and cosd(2*pi) will always evaluate to 0.994.
更多回答(1 个)
Adam
2014-11-12
编辑:Adam
2014-11-12
r=0.5*abs((sin(i-j)^2/sin(i+j)^2)+(tan(i-j)^2)/(tan(i+j)^2));
That is your maths for 'r'. Without putting it into my Matlab it seems unlikely that will return an integer every time.
Q_sun=Insd(1-r)+0.97*Insg;
That is your maths indexing into Insd, which uses 'r'. Even if 'r' were an integer though the fact you use '1-r' means you will never end up with an integer index into your Insd array unless r == 0;
2 个评论
Adam
2014-11-12
编辑:Adam
2014-11-12
You don't want a ';' at the end of that for loop line, although that maybe does no harm.
The error message tells you exactly what the problem is though despite perhaps erroneously pointing at that line.
You have stated there should be an output argument called 'absorption' yet you never create it.
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!