variable inputs function and reiteration
显示 更早的评论
Hi everyone, Is there a way to write a function with variable input and reiterated computations? for example, I have to write this function:
function[M] = fx(a1, a2, b1, b2, c1, c2, ....)
a=f(a1,a2);
b=f(b1,b2);
c=...
...
...
M=[a b c d ...];
Where f() is a generic function that I want to apply to every couple of input, and the number of these input is variable.
采纳的回答
Guillaume
2014-11-12
function M = fx(varargin)
if mod(nargin, 2) == 1
error("you must supply an even number of arguments")
end
M = [varargin{1:2:end}] .* [varargin{2:2:end}];
end
2 个评论
raffaele
2014-11-12
Guillaume
2014-11-12
It's still the same principle. This time you have to use a loop.
function M = fx(fn, varargin)
if mod(nargin, 2) == 1
error("you must supply an even number of arguments")
end
numpairs = numel(varargin) / 2;
M = zeros(1, numpairs);
for pair = 1:numpairs
M(pair) = fn(varargin{pair*2-1}, varargin{pair*2});
end
end
The bits between %% can be replaced by an arrayfun:
M = arrayfun(@(pair) fn(varargin{pair*2-1}, varargin{pair*2}), 1:numel(varargin)/2);
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