ASP-N uses incorrect position in Cleave?
4 次查看(过去 30 天)
显示 更早的评论
Hi,
Using the cleave() function, ASP-N is stated to cleave at position 2 by cleavelookup(). However, this should be clipping at position 0 (n-terminal of D residues). Can someone else verify this is functioning incorrectly?
0 个评论
采纳的回答
Luuk van Oosten
2014-11-24
Dear Ryan,
I am no expert, but I've used the cleave function before to make an in silico tryptic digest and also had some troubles using the MATLAB build-in codes for cleavage; confused me as well.
What I eventually did was use the following (and this is clearly explained in the help docs as well):
you want to use cleave and produce fragments (I presume.... your question lacks a lot of info...)
Fragments = cleave(SeqAA, PeptidePattern, Position)
so, for 'SeqAA' you put in the sequences you want to cleave. For 'PeptidePattern' you would want to use 'D' (cleave at an aspartic acid), and if you specify 'Position' as '0', it would cleave your sequences exactly as you described in your questions;
so:
SeqAA = yoursequences;
PeptidePattern = D;
Position = 0;
yourfragments = cleave(SeqAA, PeptidePattern, Position)
I guess that would do the job, but you should try it out for yourself; I have no idea what you want to do.
2 个评论
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Electrophysiology 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!