detecting elements change in an array

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Tariq Hammoudeh
Tariq Hammoudeh 2022-1-8
编辑： Tariq Hammoudeh 2022-1-8
I have an array of zeros:
x=zeros(1,36);
and in my program i change some elements of it to 1 using for example
x(6)=1;
Now i will turn some of those 1s to 2s, but is there a way i can say:
while all 1s didnt turn to 2s
.........
So basically i wanna keep inputting something as long as all the 1s didnt become 2s and it breaks out once all 1s became 2s

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采纳的回答

Walter Roberson
Walter Roberson 2022-1-8
while any(x==1)

更多回答（1 个）

Image Analyst
Image Analyst 2022-1-8
Try this:
x=zeros(1,36);
% Get 20 random indexes to turn to 1's.
indexes = sort(randperm(length(x), 20));
% Initialize by turning some of the zeros into ones.
x(indexes) = 1;
% Set up a failsafe
maxIterations = 10000; % Way more than you think it would ever need.
loopCounter = 1;
% Now loop over the 1's, turning some of them to 2's
% until all the 1's have been turned into 2.
while any(x == 1) && loopCounter < maxIterations
fprintf('Iteration #%d.\n', loopCounter)
% Get indexes that are 1.
indexes = find(x == 1)
% Pick a random one of those to turn to a 2
% or whatever method you want to use....
randomIndex = randi(length(indexes))
x(indexes(randomIndex)) = 2
loopCounter = loopCounter + 1;
end
x
fprintf('All done after %d iterations.\n', loopCounter)

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