Plotting a year by hour

2011 2 19
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I'm attempting to plot a year by date and hour. Someone suggested the following code:
D = datevec(datenum(1992,1,1:1/24:366));
which produces a years worth of data plus one hour, so I've got 01-01-1992, 0:00:00 to 31-12-1992 0:00:00. So I've got 8761 rows of data for my hours, but only 8760 rows of input data. If anyone can point me in the right direction that would be great. Thank you.

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Matt Fig
Matt Fig 2011-2-19

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Also, you realize 1992 was a leap year? Is that the year your data was taken? If it is for a generic year, why not use:
D2 = datevec(datenum(1993,1,1:1/24:365+23/24)); % makes 8760 rows

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Matt Tearle
Matt Tearle 2011-2-19

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So the issue is how to extract the first 8760 elements of a vector of 8761 points? That's easy enough:
plot(x(1:end-1),y)
Matt Tearle
Matt Tearle 2011-2-19

0 个投票

If you're starting just with data and the knowledge that it was recorded hourly throughout a given year, why not just do something like:
t = datenum(yr,1,1) + (0:(length(x)-1))/24;
D = datevec(t);
Or, alternatively
tstart = datenum(yr,1,1);
tend = datenum(yr+1,1,1) - 1/24;
n = 24*(tend-tstart) + 1;
if n==length(x)
t = linspace(tstart,tend,n);
% etc
else
error('wrong number of data points')
end

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