How using a script of variables in a parfor loop ?

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Hello,
I have gathered the declaration of variables in one and the same script, to simply reduce the number of lines in the main function. The script of variables therefore contains:
Var1 = 2;
Var2 = 3;
....
The loop just reads the script.
parfor i = 1:5
scriptOfVariables
Var3 = Var1 + Var2
end
It seems that parfor does not accept it and I have to write the set of variables directly in the loop.
Any idea to avoid overloading the loop?
  2 个评论
Ive J
Ive J 2022-1-13
why not save/load the variables in/as mat/struct? Though not sure about overhead issues (should be fine if variables are few).
Michael cohen
Michael cohen 2022-1-15
Thank you for your answer !
Because I don't want then, during the many variable calls, to have to use dot notation each time, which makes the code more cumbersome.

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采纳的回答

Matt J
Matt J 2022-1-13
编辑:Matt J 2022-1-13
Does scriptOfVariables use the loop counter i in any way? If not, you should move it outside the loop,
scriptOfVariables;
parfor i = 1:5
Var3 = Var1 + Var2;
end
Otherwise, you should be using a function instead
parfor i = 1:5
[Var1,Var2]=mfunction(i);
Var3 = Var1 + Var2;
end
  4 个评论
Matt J
Matt J 2022-1-15
From what I understand, Matlab cannot recognize structures declared outside the loop and used inside the loop.
No, that's not the problem. The problem is that you are not allowed to assign to variables declared outside the loop unless it is a sliced variable. However, you can return the struct from a function:
parfor i = 1:5
[S,Var1,Var2]=declareTemp();
Var3 = Var1 + Var2
struct.var(1).type = 6;
....
end
function [S,Var1,Var2]=declareTemp()
Var1 = 2;
Var2 = 3;
struct.var(1) = 5;
struct.var(2) = 7;
end
Michael cohen
Michael cohen 2022-1-15
Thanks again for your answer.
Actually, I simplified the example.
The reality is that the struct has multiple fields (S.var, S.coco, S.moo, etc.). So if I don't provide the structure as input parameter of the function you propose, these other fields (other than .var) will all be cleared.
[S,Var1,Var2]=declareTemp(S);
What is surprising is that parfor refuses I provide "S" as input to the declareTemp function, but it accepts the other variables (of type dooble) even though they are also declared in the script before the parfor loop
[S,Var1,Var2]=declareTemp(Var1,Var2);

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