How to find daily climatology anomaly?

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PRITAM KUMAR
PRITAM KUMAR 2022-1-14
回答： Udit06 2023-10-18
I am having 42 years of OLR data. And, i want to find daily climatology anomaly.
example:
  1. 1st jan of all 42 years I have to take and then calculate its mean
  2. than, i have to subtract the mean value to the 1st jan of every year
  3. Similarily I have to do for all the 365 days for the 42 years
How to write code for the same?
  1 个评论
dpb
dpb 2022-1-14
Look at starting with the timetable data structure and then retime and friends ("See also") You'll possibly find groupsummary of use/interest as well.

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回答（1 个）

Udit06
Udit06 2023-10-18
Hi Pritam,
I understand that you want to find the daily climatology anomaly. You can follow the following steps to achieve the same:
  1. Initialize an array to store the daily anomalies.
  2. Calculate the mean value for each day.
  3. Calculate daily climatology anomaly for each day by subracting the mean value from the given OLR data value.
Here is the code implementation of the steps mentioned above. The code given below uses a sample random data, you can replace the random data with the actual OLR data.
% Set the number of years and days
numYears = 42;
numDays = 365;
% Generate random OLR data for 42 years
olrData = rand(numDays, numYears);
% Initialize an array to store the daily anomalies
anomalyData = zeros(numDays, numYears);
% Calculate daily climatology anomaly for each day
for day = 1:numDays
climatology = mean(olrData(day, :));
anomalyData(day, :) = olrData(day, :) - climatology;
end
I hope this helps.

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