countdown the received character

3 次查看(过去 30 天)
Hi guys, I have a function which will accept the characters and n, this function is a cell array with strings of decreasing lengths, from the integer n to 1. For example, when I type buildstr('a',4), the answer should be 'abcd' 'abc' 'ab' 'a'. However the code below doesnt satisfy my requirement. Can someone point out the error code?
function str=buildstr(ch,n)
temp='';
if(n<0)
str='';
else
str=cell(n,1);
for i=n:1
if(i==1)
str(i)={char(ch)};
else
temp=char(str(i+1));
str(i)={strcat(temp,char(ch))};
end
end
end

采纳的回答

Star Strider
Star Strider 2014-11-17
You’re almost there.
if(n<0)
str='';
else
str=cell(n,1);
for i=n:-1:1
if(i==n)
str{i}=char(ch);
else
temp=char(str{i+1}+1);
str{i}=strcat(char(ch),temp);
end
end
end
There were three problems:
  1. Your loop wasn’t iterating because in MATLAB, for loops by default count upward, so if the terminal value is less than the initial value, the loop is satisfied and never iterates. You need to decrement it by telling it to count down, specifying the interval to (in this instance) to be -1;
  2. Your ‘temp’ variable subscript needs to ‘look back’ (which is to say to add 1 to ‘i’) at every iteration, and add 1 to the previous value of ‘str’;
  3. Your strcat arguments were reversed.
A minor observation: it’s best to not use ‘i’ or ‘j’ as loop counters. They are the imaginary operators in MATLAB.
  2 个评论
jarvan
jarvan 2014-11-18
i=n:-1:1 is all I need in the code, I was frustrating in counting down with for-loop. thanks for sharing your information

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Resizing and Reshaping Matrices 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by