why doesnt it work

Question

raad abzakh 2022-1-18

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1631480-why-doesnt-it-work

评论： David Hill 2022-1-19

function x = ss_dtmf(number,dt,nd,np)
nl = length(number);
x = [];
t = 0:1:nd;
t = t*dt;
tp = 0:1:np;
xp = zeros(1,length(tp));
for i=1:nl
    
    xi = ss_dtmf1(number(i),t);
    
    x = [x,xi];
    
    x = [x,xp];
end
end

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raad abzakh 2022-1-18

编辑：Walter Roberson 2022-1-18

在 MATLAB Online 中打开

this is everything i have

type firstcode
clc;
close all;
clear all;
%Time limit
Td = 2;
%Defining time interval
t = 0:0.01:Td;
% Taking input for key
n = input('Enter any number between 0-12: ');
%Assigning keys *, # to 10,11
if(n=='*')
    n = 10;
elseif(n=='#')
    n = 11;
end
% Calling the function
x = ss_dtmf1(n,t);

Function for DTMF:

function x = ss_dtmf1(n,t)
%Defining the frequencies for the keys
switch (n)
    case 1
        f1 = 697;f2 = 1209;
    case 2
        f1 = 697;f2 = 1336;
    case 3
        f1 = 697;f2 = 1477;
    case 4
        f1 = 770;f2 = 1209;
    case 5
        f1 = 770;f2 = 1336;
    case 6
        f1 = 770;f2 = 1477;
    case 7
        f1 = 852;f2 = 1209;
    case 8
        f1 = 852;f2 = 1336;
    case 9
        f1 = 852;f2 = 1477;
    case 10
        f1 = 941;f2 = 1209;
    case 0
        f1 = 941;f2 = 1336;
    case 11
        f1 = 941;f2 = 1477;
    case 12
        f1 = 0;f2 = 0;
end
x = sin(2*pi*f1.*t)+sin(2*pi*f2.*t);
figure,plot(t,x);
title(['DTMF signal for the key ' num2str(n) 'and the corresponding frequencies are ' num2str(f1) ',' num2str(f2)]);
end

Walter Roberson 2022-1-18

在 MATLAB Online 中打开

The line

Function for DTMF:

is not a valid executable line. You need to comment it out.

Cris LaPierre 2022-1-18

Try commenting out your comments so that you can run your code.

Functions must be called, so I'm asking how you are calling your function ss_dtmf? Specifically what are your input values for number, dt, nd, and np?

What error messages are you getting? Please copy and share all the red text.

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Answer 1

David Hill 2022-1-18

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1631480-why-doesnt-it-work#answer_877010

在 MATLAB Online 中打开

function x = ss_dtmf(number,dt,nd,np)
x=[];
for i=1:length(number)
    x = [x,ss_dtmf1(number(i),0:nd:dt),ss_dtmf1(12,0:np:dt)];
end
end
function x = ss_dtmf1(n,t)
   f=[941,697,697,697,770,770,770,852,852,852,941,941,0;1336,1209,1336,1477,1209,1336,1477,1209,1336,1477,1209,1477,0];
   x=sin(2*pi*f(1,n+1)*t)+sin(2*pi*f(2,n+1)*t);
end

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raad abzakh 2022-1-19

% Generation of DTMF signal for one digit

%

% Input:

% n - number of array

% dt - time increment

% nd - number of samples for each digit

% np - number of samples for each pause

%

% Output:

% x - DTMF signal

David Hill 2022-1-19

在 MATLAB Online 中打开

This should do exactly what you want.

function x = ss_dtmf(number,dt,nd,np)
x=[];
lt=linspace(0,dt,nd);
lp=linspace(0,dt,np);
for i=1:length(number)
    x = [x,ss_dtmf1(number(i),lt),ss_dtmf1(12,lp)];
end
plot(x);
end
function x = ss_dtmf1(n,t)
f=[941,697,697,697,770,770,770,852,852,852,941,941,0;1336,1209,1336,1477,1209,1336,...
    1477,1209,1336,1477,1209,1477,0];
x=sin(2*pi*f(1,n+1)*t)+sin(2*pi*f(2,n+1)*t);
end