why doesnt it work

2022 1 18
1 个回答
更新时间：2022 1 19
8 次查看（30 天）

0 个投票

function x = ss_dtmf(number,dt,nd,np)
nl = length(number);
x = [];
t = 0:1:nd;
t = t*dt;
tp = 0:1:np;
xp = zeros(1,length(tp));
for i=1:nl
xi = ss_dtmf1(number(i),t);
x = [x,xi];
x = [x,xp];
end
end

5 个评论
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Cris LaPierre
Cris LaPierre 2022-1-18
Share the complete error message you are getting, as well as the code you use to call the function ss_dtmf.
Also, please share the code for your function ss_dtmf1.
raad abzakh
raad abzakh 2022-1-18
编辑：Walter Roberson 2022-1-18
Ran in:
Ran in:
this is everything i have
type firstcode
clc; close all; clear all; %Time limit Td = 2; %Defining time interval t = 0:0.01:Td; % Taking input for key n = input('Enter any number between 0-12: '); %Assigning keys *, # to 10,11 if(n=='*') n = 10; elseif(n=='#') n = 11; end % Calling the function x = ss_dtmf1(n,t); Function for DTMF: function x = ss_dtmf1(n,t) %Defining the frequencies for the keys switch (n) case 1 f1 = 697;f2 = 1209; case 2 f1 = 697;f2 = 1336; case 3 f1 = 697;f2 = 1477; case 4 f1 = 770;f2 = 1209; case 5 f1 = 770;f2 = 1336; case 6 f1 = 770;f2 = 1477; case 7 f1 = 852;f2 = 1209; case 8 f1 = 852;f2 = 1336; case 9 f1 = 852;f2 = 1477; case 10 f1 = 941;f2 = 1209; case 0 f1 = 941;f2 = 1336; case 11 f1 = 941;f2 = 1477; case 12 f1 = 0;f2 = 0; end x = sin(2*pi*f1.*t)+sin(2*pi*f2.*t); figure,plot(t,x); title(['DTMF signal for the key ' num2str(n) 'and the corresponding frequencies are ' num2str(f1) ',' num2str(f2)]); end
raad abzakh
raad abzakh 2022-1-18
@Cris LaPierre i dont want you to solve it i jyst wanna know what can i do to solve it ive been 4 hours on this
Walter Roberson
Walter Roberson 2022-1-18
The line
Function for DTMF:
is not a valid executable line. You need to comment it out.
Cris LaPierre
Cris LaPierre 2022-1-18
Try commenting out your comments so that you can run your code.
Functions must be called, so I'm asking how you are calling your function ss_dtmf? Specifically what are your input values for number, dt, nd, and np?
What error messages are you getting? Please copy and share all the red text.

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回答（1 个）

David Hill
David Hill 2022-1-18

0 个投票

function x = ss_dtmf(number,dt,nd,np)
x=[];
for i=1:length(number)
x = [x,ss_dtmf1(number(i),0:nd:dt),ss_dtmf1(12,0:np:dt)];
end
end
function x = ss_dtmf1(n,t)
f=[941,697,697,697,770,770,770,852,852,852,941,941,0;1336,1209,1336,1477,1209,1336,1477,1209,1336,1477,1209,1477,0];
x=sin(2*pi*f(1,n+1)*t)+sin(2*pi*f(2,n+1)*t);
end

4 个评论
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raad abzakh
raad abzakh 2022-1-19
do you know how can i solve this with the codes i attached?"
id do anything
David Hill
David Hill 2022-1-19
nd and np are not defined. What do they mean?
raad abzakh
raad abzakh 2022-1-19
% Generation of DTMF signal for one digit
%
% Input:
% n - number of array
% dt - time increment
% nd - number of samples for each digit
% np - number of samples for each pause
%
% Output:
% x - DTMF signal
David Hill
David Hill 2022-1-19
This should do exactly what you want.
function x = ss_dtmf(number,dt,nd,np)
x=[];
lt=linspace(0,dt,nd);
lp=linspace(0,dt,np);
for i=1:length(number)
x = [x,ss_dtmf1(number(i),lt),ss_dtmf1(12,lp)];
end
plot(x);
end
function x = ss_dtmf1(n,t)
f=[941,697,697,697,770,770,770,852,852,852,941,941,0;1336,1209,1336,1477,1209,1336,...
1477,1209,1336,1477,1209,1477,0];
x=sin(2*pi*f(1,n+1)*t)+sin(2*pi*f(2,n+1)*t);
end
for example:
x=ss_dtmf([2 0 8 7 3 9 6 1 0 3],.1,1000,50);

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