Unexpected MATLAB operator during using isnumeric and isletter
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I am writing a function that prompts the user for a number immediately followed by a letter of the alphabet. The format should be number first then letter after. I got error when I called the function up , I typed 123d and it said Unexpected MATLAB operator.
Here is the example:
Enter a letter and a #: xyz4.5t
Error!
Enter a letter and a #: 3.21f
num =
3.2100
let =
f
And here is my code
function[num let] = readthem(word)
fprintf('Please enter a number immediately followed by a letter of the alphabet \n')
word = input('Enter a letter and a #: ')
while isnumeric(num)==0 || isletter('let')== 0
word = input('Enter a letter and a #: ')
end
sprintf('You enter %d%s',num,let)
end
采纳的回答
Jarvan,
you misused the call to input
when you use
word = input('Enter a letter and a #: ')
Matlab expects the user to give a valid expression, not a string.
what you want to do is to give a string as input, so, just do
word = input('Enter a letter and a #: ','s') % add a second argument to _input_ to consider the input as a string.
and then you can decompose the data word in two parts num and let .
Note : in your code, num and let are not calculated ?!
3 个评论
jarvan
2014-11-19
jarvan
2014-11-19
Orion
2014-11-19
in a simplier way
function [num,let] = readthem()
fprintf('Please enter a number immediately followed by a letter of the alphabet \n');
word = input('Enter a letter and a #: ','s');
let = word(isletter(word));
num = word(~isletter(word));
fprintf('You entered %s %s',num,let);
end
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