Why Value of type "tf"is not convertible to double?

Question

pawel Wisniewski 2022-1-22

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1634070-why-value-of-type-tf-is-not-convertible-to-double

评论： Cris LaPierre 2022-1-23

在 MATLAB Online 中打开

clc;

clear all;

x0=[0 0 0 0 0 0 ];

tic

xOptSim=fminsearch(@robot,x0);

car_sys = 500 s + 12500 ----------------------- 200 s^2 + 500 s + 12500 Continuous-time transfer function.

Warning: Ignoring extra legend entries.

Unable to perform assignment because value of type 'tf' is not convertible to 'double'.

Error in fminsearch (line 201)
fv(:,1) = funfcn(x,varargin{:});

Caused by:
Error using double
Conversion to double from tf is not possible.

t2=toc;

function [car_sys,u1] = robot(parametry)

X1=parametry(1);

X2=parametry(2);

X3=parametry(3);

X4=parametry(4);

X5=parametry(5);

X6=parametry(6);

m = 200; %kg

b = 500; %Ns/m

k = 12500; %N/m

car_sys = tf([b k],[m b k])

t = 0:0.001:10;

wd=7;

% Respuesta a bajas frecuencias

figure

u1 = sin(wd/2*t)+cos(wd*t);

lsim(car_sys, u1, t)

title('Niska charakterystyka częstotliwościowa')

legend('Odpowiedź systemu' , 'Lokalizacja' , 'SE')

ylim([-4 4])

end

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Answer 1

Cris LaPierre 2022-1-23

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1634070-why-value-of-type-tf-is-not-convertible-to-double#answer_879825

在 MATLAB Online 中打开

I believe the issue is because the order of your function outputs is not correct. The first output of your function needs to be the solution, u1. Try reversing the order of your output arguments.

x0=[0 0 0 0 0 0 ];

xOptSim=fminsearch(@robot,x0);

car_sys = 500 s + 12500 ----------------------- 200 s^2 + 500 s + 12500 Continuous-time transfer function.

Warning: Ignoring extra legend entries.

Unable to perform assignment because the size of the left side is 1-by-1 and the size of the right side is 1-by-10001.

Error in fminsearch (line 201)
fv(:,1) = funfcn(x,varargin{:});

function [u1,car_sys] = robot(parametry)

X1=parametry(1);

X2=parametry(2);

X3=parametry(3);

X4=parametry(4);

X5=parametry(5);

X6=parametry(6);

m = 200; %kg

b = 500; %Ns/m

k = 12500; %N/m

car_sys = tf([b k],[m b k])

t = 0:0.001:10;

wd=7;

% Respuesta a bajas frecuencias

figure

u1 = sin(wd/2*t)+cos(wd*t);

lsim(car_sys, u1, t)

title('Niska charakterystyka częstotliwościowa')

legend('Odpowiedź systemu' , 'Lokalizacja' , 'SE')

ylim([-4 4])

end

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Cris LaPierre 2022-1-23

The new error is because your solution vector, u1, is not the same size as x0. One thing to look into is why you are not using your X values in your function.

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