How to reshape an array into 3 different matrix with different sizes?

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Hana
Hana 2014-11-19
编辑： Matt J 2014-11-19
I want to reshape A into 3 matrices m1,m2,m3:
A=[1 2 3 4 5 6 7 8 9 4 5 3 5 3 2 5 4 2 4 7 5 ];
m1=-9999*ones(3,3);
m2=-9999*ones(2,2);
m3=-9999*ones(2,4);
the result should look like:
m1=[1 2 3 ;4 5 6 ;7 8 9];
m2=[4 5 ;3 5];
m3=[3 2 5 4; 2 4 7 5];
  1 个评论
David Young
David Young 2014-11-19
"Reshape" normally means to change the shape but keep the same number of elements. Here, though, all the matrices have different numbers of elements. Please could you define the operation you need more exactly?

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采纳的回答

Shane
Shane 2014-11-19
It looks like you just want to split the array up.
A=[1 2 3 4 5 6 7 8 9 4 5 3 5 3 2 5 4 2 4 7 5 ];
subData1 = A(1:9);
subData1 = reshape(subData1, [3 3]);
subData2 = A(10:13);
subData2 = reshape(dubData2, [2 2]);
subData3 = A(14:21);
subData3 = reshape(subData3, [ 4 4]);
This is all manually mind you. If your data structure will change dynamically you will want to try something different.

更多回答（1 个）

Matt J
Matt J 2014-11-19
编辑：Matt J 2014-11-19
After the lines you've shown with m123=-9999*ones(...) do the following
m1(:)=A(1:9);
m2(:)=A(10:13);
m3(:)=A(14:end);
and transpose as needed.

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