How to remove the number 0 between index1 & index2 ?

There you have it. The tricky thing here is that you have to create a vector of the same length as your input, whose values are zero or one if it satisfies both conditions or not, respectively.

% Inputs
A0 = [0 0 0 1 1 1 1 0 0 0 2 2 1 0 0 0 1 1 0 0 0];
ind_1 = 4;
ind_2 = length(A0) - 4;
loc_value = 0;
% Constants
A = A0;
N = length(A);
% Set range
range = ind_1:ind_2;
% Set condition
cond_1 = A == loc_value;
cond_2 = zeros(1, N);
for i = 1:N
    if i >= ind_1 && i <= ind_2
        cond_2(i) = 1; % Is in range
    end
end
% Remove loc_value from index_1 to index_2
A(cond_1 & cond_2) = [];
% Result
A
A = 1×15
     0     0     0     1     1     1     1     2     2     1     1     1     0     0     0
% Check
sol = [0 0 0 1 1 1 1 2 2 1 1 1 0 0 0];
isequal(A, sol)
ans = logical
   1

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Answer 2

DGM 2022-1-25

0
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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1635635-how-to-remove-the-number-0-between-index1-index2#answer_881275

编辑：DGM 2022-1-25

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Assuming that you're only concerned with zeros between 1 or 2, and that all values are single-digit numbers, here's one way:

A = [0 0 0 1 1 1 1 0 0 0 2 2 1 0 0 0 1 1 0 0 0];
B = regexprep(char(A+'0'),'(?<=[1|2])0+(?=[1|2])','')-'0'
B = 1×15
     0     0     0     1     1     1     1     2     2     1     1     1     0     0     0

If you want any nonzero digits to be considered:

A = [0 0 0 1 1 1 3 0 0 0 2 2 1 0 0 0 9 1 0 0 0];
B = regexprep(char(A+'0'),'(?<=[1-9])0+(?=[1-9])','')-'0'
B = 1×15
     0     0     0     1     1     1     3     2     2     1     9     1     0     0     0

If the numbers aren't single-digit and you want to get rid of zeros between any nonzero numbers, this is a different way:

idx1 = find(A ~= 0,1,'first');
idx2 = find(A ~= 0,1,'last');
D = A(idx1:idx2);
D = [max(A(1:idx1-1),0) D(D~=0) min(A(idx2+1:end),numel(A))]
D = 1×15
     0     0     0     1     1     1     3     2     2     1     9     1     0     0     0