How to generate string without space at the beginning?

YZ
2014 11 20
3 个回答
回答已采纳
更新时间：2014 11 20
5 次查看（30 天）

0 个投票

FieldsLetter = repmat('Item_',16,1);
FieldsDigit = num2str(transpose(2:2:16),'%1d');
Fields = strcat(FieldsLetter, FieldsDigit);
The result from above code is Fields =
Item_ 2
Item_ 4
Item_ 6
Item_ 8
Item_10
Item_12
Item_14
Item_16
But what I want is Fields =
Item_2
Item_4
Item_6
Item_8
Item_10
Item_12
Item_14
Item_16
So how to generate string by using num2str without the space at the beginning? Thank you.

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 采纳的回答

Kelly Kearney
Kelly Kearney 2014-11-20

2 个投票

Easier, you can just add the string part to the num2str format:
Fields = num2str((2:2:16)', 'Item_%d');
Of course, this right-justifies the final results, which may or may not matter to you. If you're looking to get a cell array of strings eventually, you can quickly trim the extra whitespace:
Fields = strtrim(cellstr(num2str((2:2:16)', 'Item_%d')))

更多回答（2 个）

Star Strider
Star Strider 2014-11-20

1 个投票

Change '%1d' to '%-1d'. The ‘-’ in front of the format descriptor left-justifies it.
FieldsLetter = repmat('Item_',8,1);
FieldsDigit = num2str(transpose(2:2:16),'%-1d');
Fields = strcat(FieldsLetter, FieldsDigit);
per isakson
per isakson 2014-11-20
编辑：per isakson 2014-11-20

1 个投票

num2str creates a rectangular character array. The "extra" space can be moved to the end of the string. If that's ok
Replace
FieldsDigit = num2str(transpose(2:2:16),'%1d');
by
FieldsDigit = num2str(transpose(2:2:16),'%-2d');
And read the documentation on num2str. Note:
'–' Left-justify. Example: %-5.2f
An alternative is to insert a leading zero
FieldsDigit = num2str(transpose(2:2:16),'%02d');

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