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how to form loop to jump from one element of matrix to other element.

1 次查看(过去 30 天)
Hi friends,
N_temp_failure= [ 938 945 955 2002 2003 4565 4566 4567 ];
Nx=937;
while Nx<=4567 ( i mean last element of N_temp_failure ).
Nx=Nx+0.001;
if Nx ==938
Nx= 945-1; (i mean it should jump to second element of N_temp_failure subtracted by 1 )
else
Nx=Nx;
end
end
it should repeat after Nx reaches every element of N_temp_failure, until it reaches the last element. N_temp_failure will always be in ascending order.
Please help me,
Advance Thanks Jagadesh Rao Thalur
  2 个评论
Thorsten
Thorsten 2014-11-21
编辑:Thorsten 2014-11-21
Add 0.001 to each element of N_temp_failure, unless the i'th element is 938, in this case you have to subtract 1 from the ith and the ith+1 element; is that what you want?

回答(1 个)

Manoj
Manoj 2014-11-21
Does this do what you want ?
N_temp_failure= [ 938 945 955 2002 2003 4565 4566 4567 ];
for ii=1:size(N_temp_failure,2)-1
Nx=N_temp_failure(ii)-1;
while Nx <= N_temp_failure(end);
Nx=Nx+0.001;
if Nx==N_temp_failure(ii)
Nx=N_temp_failure(ii+1)-1;
else
Nx=Nx;
end
end
end
  2 个评论
Jagadesh Rao
Jagadesh Rao 2014-11-21
actually your answer is partially correct, you should have put for loop inside while loop, you did the opposite. thanks
Jagadesh Rao
Jagadesh Rao 2014-11-22
I tried this , this didn't work, it doesn't give the jump i asked for.
please try some other way.

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