How to draw same size rectangle on different image location

Question

Tania 2014-11-21

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https://ww2.mathworks.cn/matlabcentral/answers/163758-how-to-draw-same-size-rectangle-on-different-image-location

评论： Tania 2014-11-22

采纳的回答： Image Analyst

在 MATLAB Online 中打开

Hi,

I have selected random points using the below code

m = imread('a.jpg');
figure, imshow(m);
random_num = 50;
l = randi(numel(m), 1, random_num);
m(l) = 255;
figure, imshow(m);

Now I want to draw circle/rectangle for each random points. circle/rectangle for all points will be of equal size.

Can anyone assist me how to do that please.

Added an image for your information.

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Answer 1

Image Analyst 2014-11-22

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https://ww2.mathworks.cn/matlabcentral/answers/163758-how-to-draw-same-size-rectangle-on-different-image-location#answer_159834

circles_demo.m

See attached demo.

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Image Analyst 2014-11-22

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Well that was just my canned demo. I expected you to adapt it. Here, I adapted it some for you. You still have to do it for every color channel if you have a color image, and apply it to an existing photo instead of a blank canvass if that's what you need.

% M-file to place multiple small circles in an image.
% Clean up
close all;
clc;
fontSize = 15;
% Initialize some parameters.
numberOfSmallCircles = 25; % Number of small circles
smallCircleOutsideValue = 0.2;
smallCircleInsideValue = 0.8;
smallCircleRadius = 25;    % small circle radius
bigImageWidth = 500;
bigImageHeight =  500; % square area 0f 500*500
% Initialize an image to hold one single small circle.
smallCircleImage = zeros(2*smallCircleRadius, 2*smallCircleRadius);
[x, y] = meshgrid(1:smallCircleRadius*2, 1:smallCircleRadius*2);
singleCircleImage = zeros(2*smallCircleRadius, 2*smallCircleRadius);
singleCircleImage((x - smallCircleRadius).^2 + (y - smallCircleRadius).^2 <= smallCircleRadius.^2) = smallCircleInsideValue;
% Display it in the upper right plot.
subplot(1,2, 1);
imshow(singleCircleImage, []);
axis on;
title('Single Small Circle (scaled to fit)', 'FontSize', fontSize);
% Enlarge figure to full screen.
set(gcf, 'Units', 'Normalized', 'Outerposition', [0, 0, 1, 1]);
singleWidth = size(singleCircleImage, 2);
singleHeight = size(singleCircleImage, 1);
% Get random coordinates in the big image where
% we will place the upper left corner of the small circle.
widthThatWillFit = bigImageWidth - 2 * smallCircleRadius;
heightThatWillFit = bigImageHeight - 2 * smallCircleRadius;
smallUpperLeftX = widthThatWillFit * rand(numberOfSmallCircles, 1);
smallUpperLeftY = heightThatWillFit * rand(numberOfSmallCircles, 1);
% Initialize an output image to hold many small overlapping circles.
manySmallCircles = zeros(bigImageHeight, bigImageWidth);
% Place the small circles one by one.
for k = 1 : numberOfSmallCircles
  % Find the square in the big image where we're going to add a small circle.
  x1 = int16(smallUpperLeftX(k));
  y1 = int16(smallUpperLeftY(k));
  x2 = int16(x1 + singleWidth - 1);
  y2 = int16(y1 + singleHeight - 1);
  % Add in one small circle to the existing big image.
  manySmallCircles(y1:y2, x1:x2) = manySmallCircles(y1:y2, x1:x2) + singleCircleImage;
end
% Make outside the circles the outside color.
manySmallCircles(manySmallCircles == 0) = smallCircleOutsideValue;
% Display it in the lower left plot.
subplot(1,2, 2);
imshow(manySmallCircles);
axis on;
title('Many Small Overlapping Circles', 'FontSize', fontSize);

Tania 2014-11-22

在 MATLAB Online 中打开

    I am pretty close to it from your code. But one issue I am having is I do not want to fill the circle and need to see the center of each circle.
    I am trying to do this:
% M-file to place multiple small circles in an image.
% Clean up
close all;
clc;
fontSize = 15;
% Initialize some parameters.
numberOfSmallCircles = 25; % Number of small circles
smallCircleOutsideValue = 0.2;
smallCircleInsideValue = 0.8;
smallCircleRadius = 25;    % small circle radius
bigImageWidth = 500;
bigImageHeight =  500; % square area 0f 500*500
smallCircleImage = zeros(2*smallCircleRadius, 2*smallCircleRadius);
[x, y] = meshgrid(1:smallCircleRadius*2, 1:smallCircleRadius*2);
singleCircleImage = zeros(2*smallCircleRadius, 2*smallCircleRadius);
singleCircleImage((x - smallCircleRadius).^2 + (y - smallCircleRadius).^2 <= smallCircleRadius.^2) = smallCircleInsideValue;
singleWidth = size(singleCircleImage, 2);
singleHeight = size(singleCircleImage, 1);
% Get random coordinates in the big image where
% we will place the upper left corner of the small circle.
widthThatWillFit = bigImageWidth - 2 * smallCircleRadius;
heightThatWillFit = bigImageHeight - 2 * smallCircleRadius;
smallUpperLeftX = widthThatWillFit * rand(numberOfSmallCircles, 1);
smallUpperLeftY = heightThatWillFit * rand(numberOfSmallCircles, 1);
% Initialize an output image to hold many small overlapping circles.
manySmallCircles = zeros(bigImageHeight, bigImageWidth);
% Place the small circles one by one.
for k = 1 : numberOfSmallCircles
  % Find the square in the big image where we're going to add a small circle.
  x1 = int16(smallUpperLeftX(k));
  y1 = int16(smallUpperLeftY(k));
  x2 = int16(x1 + singleWidth - 1);
  y2 = int16(y1 + singleHeight - 1); 
      linearIndices = randi(numel(manySmallCircles), 1, k);
      % Set those lcoations to be white.
      manySmallCircles(linearIndices) = 1;
  % Add in one small circle to the existing big image.
  manySmallCircles(y1:y2, x1:x2) = manySmallCircles(y1:y2, x1:x2) + singleCircleImage;
end
figure, imshow(manySmallCircles);
 When I have used 
   linearIndices = randi(numel(manySmallCircles), 1, k);
      % Set those lcoations to be white.
      manySmallCircles(linearIndices) = 1;

this to see if it the circles are drawn based on the selected random points it seems it is giving me different points and circles are in different points.

Not sure what I am doing wrong.

If I use them outside the loop it is not working as well because it is obvious that it will select different points.

Tania 2014-11-22

Thank you Image analyst. I have used separate channels to do what you have said. Not perfect but I am happy.

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Answer 2

Youssef Khmou 2014-11-22

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在 MATLAB Online 中打开

Try to adjust this protocol to your problem :

 L=0.5;
 N=100;
 for n=1:N
 p=randn;
 p2=randn;
 r=p+L;
 r2=p2+L;
 x=[p r r p p];
 y=[p2 p2 r2 r2 p2]; plot(x,y,'k')
 hold on;
 end
 title(' Random positions of same size rectangles')

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Tania 2014-11-22

编辑：Tania 2014-11-22

Trying to figure out your code how to use it in my color image not in a white blank image window but can not figure it out.

Tania 2014-11-22

I have figured it out with your one as well. Thank you very much.

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Answer 3

Ahmet Cecen 2014-11-21

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This is a filter operation. I am 95% sure you cancan get away with using imdilate with a circle or square structral element of your liking. Basically make your randomcpoints 1 and everything else 0, and dilate that image.

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Tania 2014-11-22

Yes you are right.

I have a color image. in that image I have selected some random points. I want to draw circles in that image using the random point location.

Image Analyst 2014-11-22

Isn't that what I showed in my answer?

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How to draw same size rectangle on different image location

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