loop in function inside
显示 更早的评论
kk1
function kk1
clc;clear;close all;
l=633;
c = 1;
k0=2*pi/l;
ea=1.39;
da=1:300;
theta=1:70;
y=zeros(length(theta),length(da));
np=1.5;
x=(2*pi/l)*np*sind(theta);
function y=f(theta,da)
for i=1:length(theta)
iter = 0;
for j=1:length(da)
iter
ka=k0*sqrt(ea-x.^2);
f=(1-exp(2*1i.*da(j).*ka(i)))/(1+exp(2*1i.*da(j).*ka(i)));
%pfms=2*atan(1i*a.*b);
y(i,j)=2*atan(1i*c.*f);
% disp(y);
iter = iter + 1;
end
end
end
plot(da,y )
end
why this is not working how to make looping in function and find its derivative w r to da i.e df/dda with out syms and help to plot any one
6 个评论
Matt J
2022-1-29
In what way are we to see that it isn't working?
shiv gaur
2022-1-29
Cris LaPierre
2022-1-29
Sure it does. It's plotting exactly what you are telling it to plot: (da,y)
David Hill
2022-1-29
You never call your function f. What computation are you trying to do? Your code makes no sense.
other type with out function showing some value given in fig
why is so
% Edit - easier to view the fig here than download it
openfig('fig.fig');
Cris LaPierre
2022-1-29
You never call (run) your function.
采纳的回答
You must call the function f() somwhere. Your code defined f() but never used it; that's why there was an empty plot: y was not updated.
kk1(); % here I am calling your main function kk1
function kk1
clc;clear;close all;
l=633;
c = 1;
k0=2*pi/l;
ea=1.39;
da=1:300;
theta=1:70;
% y=zeros(length(theta),length(da));
np=1.5;
x=(2*pi/l)*np*sind(theta);
y = f(theta,da); % here your main function kk1 is calling the nested function f
plot(da,y);
function y=f(theta,da)
y=zeros(length(theta),length(da));
for i=1:length(theta)
iter = 0;
for j=1:length(da)
% iter
ka=k0*sqrt(ea-x.^2);
f=(1-exp(2*1i.*da(j).*ka(i)))/(1+exp(2*1i.*da(j).*ka(i)));
%pfms=2*atan(1i*a.*b);
y(i,j)=2*atan(1i*c.*f);
% disp(y);
iter = iter + 1;
end
end
end
end
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