Loop to generate Histogram
显示 更早的评论
I have two random numbers and add them together.
a_x = (-2.5 + (2.5+2.5)*rand(1,1));
a = 5*1e-9;
b = 0;
a_z = a.*randn(1,1) + b;
A = a_x + a_z
Step 1:
Now I want to do this 100 times and create the histogram of all the results of A.
Step2:
Then I want to sort the values in ascending order.
Can someone please explain me how to do the two steps?
5 个评论
Ankit
2022-1-31
but in above problem, you forgot to mentioned about a_y and Z1
Step 1: using for loop
Step 2: using sort command. Sort array elements - MATLAB sort - MathWorks Deutschland
Lucas Kellermann
2022-1-31
Arif Hoq
2022-1-31
What is Z1?
Lucas Kellermann
2022-1-31
Step 1: using for loop:
read more about for loop for loop to repeat specified number of times - MATLAB for - MathWorks Deutschland
a = 5*1e-9;
b = 0;
a_x = zeros(100,1);
a_z = zeros(100,1);
A = zeros(100,1);
for i= 1:100
a_x(i) = (-2.5 + (2.5+2.5)*rand(1,1));
a_z(i) = a.*randn(1,1) + b;
A(i) = a_x(i) + a_z(i);
end
histogram(A)
Step 2: try by yourself :)
采纳的回答
You can achieved the same without using loop.
n = 100 ;
a_x = (-2.5 + (2.5+2.5)*rand(n,1));
a = 5*1e-9;
b = 0;
a_z = a.*randn(1,1) + b;
A = a_x + a_z ;
histogram(A)
To sort the values, you can use function sort. Read about it.
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Data Distribution Plots 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
