Delete Cells in Cell array in two loops....
显示 更早的评论
Hi everyone,
I have the following code and want to delete the empty cells in the results:
tt1 = find(year(Time) == 2015 & month(Time) == 10);
tt2 = find(year(Time) == 2010 & month(Time) == 10);
tt3 = find(year(Time) == 2019 & month(Time) == 04);
JT = [ tt1; tt2; tt3 ];
H= [ 4, 8];
for h = H
for jt = JT'
PdfDat{h,jt+h}=strcat('T',num2str(year(Time(jt+h))), 'Q', num2str(ceil(month(Time(jt+h)) / 3)));
Pdfd{h,jt+h}=ResMatch_LU.PST(jt+h, :);
end
end
The results are the following in which I want to delete the [ ] such that the array will be presented in fucntion of 'h' and 'jt+h' :
I want also to delete [ ] in the cell "1x401 double" here in coulumns 52 and 56;
Could you please help me to do those changes? My Matlab version is R2015a.
Many thanks!
回答（1 个）
Ankit
2022-1-31
'isempty' -- true for cells containing an empty array, false otherwise
PdfDat_new = PdfDat(~cellfun('isempty',PdfDat));
Pdfd_new = Pdfd(~cellfun('isempty',Pdfd));
8 个评论
Thank you Ankit
Your code lines provide the below results, wile I want that those results be presented in function of "h". In other words, I need to have 2 cells of (3x1 cell) for each "H" instead of the below 6x1 cells. How to do that?
I want that for each H , we have :
Ankit
2022-2-1
PdfDat_new = reshape(PdfDat(~cellfun('isempty',PdfDat)),2,[])';
PdfDat_new1 = out(:,1); % 3x1 cell
PdfDat_new2 = out(:,2); % 3x1 cell
Ibrahs
2022-2-1
Thank you Ankit,
I got the following error with reshape:
Also, I don't have the "out ()" function with my R2015a version.
When I correctly use "Reshape", PdfDat_new = reshape(PdfDat(~cellfun('isempty',PdfDat)),[],1)';
I am getting the following cells which should not be split uniformly in two cells, rather I need to have here
PdfDat_new1 = [PdfDat_new(1,1), PdfDat_new(1,3), PdfDat_new(1,5)];
PdfDat_new2 = [PdfDat_new(1,2), PdfDat_new(1,4), PdfDat_new(1,6)];
These cells are in function of "H".
How can I do that? And how can I overcome the issue with the function "Out"?
Many thanks again
Ankit
2022-2-1
PdfDat_new1 = PdfDat_newout(1:2:5,:);
PdfDat_new2 = PdfDat_newout(2:2:6,:);
You can also use for loop and other ways to achieve as per your requirement
Rik
2022-2-1
You should avoid numbered variables. It sounds like the number of PdfDat_new variables can change. If you can't guarantee that there will only be exactly 2, you should consider putting them in a cell array so you can index them in a loop.
Ibrahs
2022-2-1
Ankit
2022-2-1
why dont you use the method mentioned by rik? here with limited info and without having your relevant file it is not easy to reproduce the same problem
Rik
2022-2-1
It would probably help if you replace this loop:
for h=H
with this loop:
for n_H=1:numel(H)
h=H(n);
...
PdfDat_new{n_H}=...
类别
在 帮助中心 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
