integral calculation size problem

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Xuejian Niu
Xuejian Niu 2022-2-4
回答： Steven Lord 2022-2-4
a = 0.6;
% Define pu and pL
PU = 130000*exp(-x./(10*a));
PL = 150000*exp(-x./(10*a));
% integral cal
fun1 = @(x) (PL - PU);
N1 = integral(fun1,0,3*a);
% the matlab shows me a error here (output of function must be same size as input)
% Actually, I am not show where the error is, could you help me to fix it?

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回答（2 个）

Arif Hoq
Arif Hoq 2022-2-4
编辑：Arif Hoq 2022-2-4
Ran in:
i took the value of x=10, because you did not mention that. you need to mention ArrayValue as true, cause you are using the function as array/vector value
a = 0.6;
x=10;
% Define pu and pL
PU = 130000*exp(-x./(10*a));
PL = 150000*exp(-x./(10*a));
% integral cal
fun1 = @(x) (PL - PU);
N1 = integral(fun1,0,3*a,'ArrayValued', true)
N1 = 6.7995e+03
Steven Lord
Steven Lord 2022-2-4
Ran in:
a = 0.6;
% Define pu and pL
Make PU and PL functions of x.
PU = @(x) 130000*exp(-x./(10*a));
PL = @(x) 150000*exp(-x./(10*a));
% integral cal
Call those functions in your integrand.
fun1 = @(x) (PL(x) - PU(x));
N1 = integral(fun1,0,3*a)
N1 = 3.1102e+04

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