When i run my code it says Unrecognized function or variable A.

Question

Tasos Apostolopoulos 2022-2-4

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1643335-when-i-run-my-code-it-says-unrecognized-function-or-variable-a

回答： Davide Masiello 2022-2-4

function res = my_matlab_function(A,N)
A=4;
N=30;
y(1)=1/2*(3+(A^2/3));
y(2)=1/2*(y(1)+(A^2/y(1)));
y(3)=1/2*(y(2)+(A^2/y(2)));
y(4)=1/2*(y(3)+(A^2/y(3)));
y(5)=1/2*(y(4)+(A^2/y(4)));
for n=6:(N-1)
    y(n)=1/2*(y(n-1)+A^2/y(n-1));
end
res=y(end);
disp(['A= ' num2str(A) 'Result=' num2str(res)])
end
  
%when i call my function:
result = my_matlab_function(A,N)
disp(['A= ' num2str(A) 'Result=' num2str(result)])

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Davide Masiello 2022-2-4

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1643335-when-i-run-my-code-it-says-unrecognized-function-or-variable-a#answer_889105

在 MATLAB Online 中打开

You need to define A and N before passing them to the function.

Try this:

A = 4;
N = 30;
result = my_matlab_function(4,30);
function res = my_matlab_function(A,N)
y(1)=1/2*(3+(A^2/3));
y(2)=1/2*(y(1)+(A^2/y(1)));
y(3)=1/2*(y(2)+(A^2/y(2)));
y(4)=1/2*(y(3)+(A^2/y(3)));
y(5)=1/2*(y(4)+(A^2/y(4)));
for n=6:(N-1)
    y(n)=1/2*(y(n-1)+A^2/y(n-1));
end
res=y(end);
fprintf('A = %d\n',A)
fprintf('Result = %d\n',res)
end