Linear approximation that goes through zero
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Hello, I have a few points, and I need to approximate them with linear function that goes through zero. Any ideas?) Thank you in advance)
3 个评论
Mathieu NOE
2022-2-7
HI
have you tried with 1st order polynomial (using polyfit) ?
@Mathieu NOE I was going to suggest the way Matt did it
x=0:5 + 3;
y = 1.5 * x + randn(size(x)) * 0.4 + 10;
slope = x(:) \ y(:);
yFitted = slope * x;
plot(x,y,'.',x,yFitted, 'MarkerSize', 20);
grid on;
Is there a way to get the offset to be zero with polyfit()?
Mathieu NOE
2022-2-7
seems the topic has been already debated quite often
solutions from FEX :
采纳的回答
Here's a simple example.
x=-5:5;
y=2*x+randn(size(x))*0.4;
slope=x(:)\y(:);
yapprox=slope*x;
plot(x,y,'o',x,yapprox);
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